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nikitadnepr [17]
3 years ago
11

What formula should I use?

Physics
1 answer:
Elodia [21]3 years ago
7 0
These nuts on your chin
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A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.
Len [333]

Explanation:

Given

Velocity v = 23.0m/s

Distance S = 3.45m

Required

Time it will take the skier to reach the ground;

Using the equation of motion;

S = ut + 1/2gt²

3.45 = 23t + 1/2(9.8)t²

3.45 = 23t + 4.9t²

4.9t²+23t-3.45 = 0

Factorize;

t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)

t = -23 ±√529+67.62/9.8

t = -23±√596.62/9.8

t = -23±24.43/9.8

t = 1.43/9.8

t = 0.146 secs

Hence take the skier 0.146 secs to reach the ground.

b) Horizontal distance covered is the range;

Range = U√2H/g

Range = 23√2(3.45)/9.8

Range = 23√6.9/9.8

Range = 23√0.7041

Range = 23(0.8391)

Range = 19.29m

Hence the horizontal distance travelled in air is 19.29m

7 0
3 years ago
A rogue band of colonists on the moon declares war and prepares to use a catapult to launch large boulders at the earth. Assume
insens350 [35]

Answer:

  • 2.3 km/s
  • 11 km/s

Explanation:

The system is made up of three body system which are the boulder, earth and the moon also the sum of potential ad kinetic energies are assumed to be the same also note that the boulder was launched from the moon at an initial velocity

A ) Minimum speed of the boulder for it to reach the earth = 2.3 km/s

B) ignoring air resistance the impact speed on earth of a boulder launched at this minimum speed = 11 km/s

find attached the solution in details

4 0
3 years ago
A 65-kg bungee jumper, who is attached to one end of an 85-m long bungee cord that has its other end tied to a bridge, jumps off
irinina [24]

Answer:

The impulse delivered to the bungee jumper is 1.32 kN.s

Explanation:

The situation can be shown graphically as shown in the figure.

Impulse delivered to the bungee jumper = Area under the curve.

The curve represents a triangle and the area of traiangle = (1/2)base×height

The base of the triangle from the graph = 1.2 seconds.

The height of the triangle from the graph = 2.2 kN

Thus,

<u>Impulse = (1/2)×(1.2 seconds)×(2.2 kN) = 1.32 kN.s</u>

3 0
3 years ago
How does the density of the Earth’s core compare to the other layers of the Earth?
Delvig [45]
The answer is A) for sure
3 0
3 years ago
Read 2 more answers
What force is required to accelerate a body with the mass of 15 kilograms at a rate of 8m/s2?
Tom [10]
Force = mass * acceleration
F = 15 *8 = 120 Newton
8 0
4 years ago
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