A water wave is an example of a mechanical wave. A wave that can travel only through matter is called a mechanical wave.
Answer
given,
mass of the crate = 53 Kg
force applied by the worker = 180 N
Angle made with the horizontal = 35°
crate moves = 2.9 m
a) The work done equals the force in the direction of the displacement, times the displacement
W = F_x ×d
W = 180 cos 35° × 2.9
W = 427.6 J
b) A force that is perpendicular to the direction of the displacement does not do any work so work done by gravitational force is zero
c) Similarly for the normal force the work done will be zero.
d) Total work done by the crate is equal to 427.6 J
The formula for Fahrenheit and Celsius conversion is
T(°F)<span> = </span>T(°C)<span> × 1.8 + 32
where T is temperature in F or C ( Fahrenheit or Celsius whatever is the case)
</span>This means that keeping this FORMULA in mind we can add different values to it and accordingly convert values from one to another.
Some examples of fahrenheit conversions to Celsius are :
32°F = 0°C using F = (0 x 1.8) + 32
Answer:
The magnitude of the change in the momentum of the ball during the rebound is 4.4 kg-m/s.
Explanation:
Given that,
Mass of the ball, m = 0.1 kg
Initial speed of the ball, u = 25 m/s
Final speed of the ball, v = -19 m/s (the ball rebounds so it will be negative)
We need to find the magnitude of the change in the momentum of the ball during the rebound. The change in momentum of the object is equal to the difference of final and initial momentum.



or

So, the magnitude of the change in the momentum of the ball during the rebound is 4.4 kg-m/s. Hence, this is the required solution.
Answer:
5.49×10¯⁴ m²
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 2.22×10¯⁴ m
Charge (Q) = 5.24×10¯⁹ C
Potential difference (V) = 240 V
Permittivity of free space (ε₀) = 8.85×10¯¹² F/m
Area (A) =?
Thus, the area of the plate can be obtained as follow:
Q = ε₀AV /d
5.24×10¯⁹ = 8.85×10¯¹² × A × 240 / 2.22×10¯⁴
5.24×10¯⁹ = 2.12×10¯⁹ × A / 2.22×10¯⁴
Cross multiply
2.12×10¯⁹ × A = 5.24×10¯⁹ × 2.22×10¯⁴
Divide both side by 2.12×10¯⁹
A = (5.24×10¯⁹ × 2.22×10¯⁴) / 2.12×10¯⁹
A = 5.49×10¯⁴ m²
Thus, the area of the plates is 5.49×10¯⁴ m².