Answer:
v
2
=v
0
2
+2aΔxv, squared, equals, v, start subscript, 0, end subscript, squared, plus, 2, a, delta, x
Explanation:
Answer:
-you have to make yourse;f as light as possible so toss your bag, jacket, and shoes.
-Try to take a few steps backwards.
-Keep your arms up and out of the quicksand.
-Try to reach for a branch or person's hand to pull yourself out.
-Take deep breaths.
-Move slowly and deliberately.
Answer:
Explanation:
In a frictionless system with no acceleration, the tension in the rope must be F along its entire length
FBD analysis of the lower pulley has two upward acting tension vectors F and one downward acting weight vector W
2F = W
F = W/2
FBD analysis of the upper pulley has one upward acting support vector T and three downward acting tension vectors F
T = 3F
T = 3(W/2)
T = 1.5W
Answer:
76.73 ft/s
Explanation:
Let the final velocity is v.
initial velocity, u = 96 ft/s
g = 32 ft/s²
height, h = 52 feet
use third equation of motion
v² = u² - 2 gh
v² = 96 x 96 - 2 x 32 x 52
v = 76.73 ft/s
Thus, the speed of the ball as it reaches the ground is 76.73 ft/s.
Answer:
v = 17.66 m/s
Explanation:
As we know that the lower end of the pole is fixed in the ground and it start rotating about that end
so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end
so we have
so we have
now we have
now the speed of the other tip of the pole is given as
