When a light wave strikes an object, it can be absorbed, reflected, or refracted by the object. All objects have a degree of reflection and absorption. ... In the natural world, light can also be transmitted by an object. That is, light can pass through an object with no effect (an x-ray, for example).
Given data:
* The mass of the baseball is 0.31 kg.
* The length of the string is 0.51 m.
* The maximum tension in the string is 7.5 N.
Solution:
The centripetal force acting on the ball at the top of the loop is,
![\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20T%2Bmg%3D%5Cfrac%7Bmv%5E2%7D%7BL%7D_%7B%7D%20%5C%5C%20v%5E2%3D%5Cfrac%7BL%28T%2Bmg%29%7D%7Bm%7D%20%5C%5C%20v%3D%5Csqrt%5B%5D%7B%5Cfrac%7BL%28T%2Bmg%29%7D%7Bm%7D%7D%20%5Cend%7Bgathered%7D)
For the maximum velocity of the ball at the top of the vertical circular motion,
![v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}](https://tex.z-dn.net/?f=v_%7B%5Cmax%20%7D%3D%5Csqrt%5B%5D%7B%5Cfrac%7BL%28T_%7B%5Cmax%20%7D%2Bmg%29%7D%7Bm%7D%7D)
where g is the acceleration due to gravity,
Substituting the known values,
![\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20v_%7B%5Cmax%20%7D%3D%5Csqrt%5B%5D%7B%5Cfrac%7B0.51%287.5_%7B%7D%2B0.31%5Ctimes9.8%29%7D%7B0.31%7D%7D%20%5C%5C%20v_%7B%5Cmax%20%7D%3D%5Csqrt%5B%5D%7B%5Cfrac%7B0.51%2810.538%29%7D%7B0.31%7D%7D%20%5C%5C%20v_%7B%5Cmax%20%7D%3D%5Csqrt%5B%5D%7B17.34%7D%20%5C%5C%20v_%7B%5Cmax%20%7D%3D4.16%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.
That depends on where you weigh it.
-- On Earth, it weighs 9.807 newtons (2.205 pounds).
-- On the moon, it weighs 1.623 newtons (5.84 ounces).
-- On Jupiter, it weighs 24.79 newtons (5.57 pounds).
BTW ... 1,000 grams of mass is called ' one kilogram '.
Dimensional analysis is a method of checking the dimensions of each value in an equation. I will give you an example.

Is a know equation which equates energy and mass. So our question is, is this true or not? The method is following:
knowing that c has the dimension of [m/s] and m has [kg], what is the dimension of E? So here the dimensional analysis begins.
![E = mc^2 \Rightarrow [E] = \text{kg} \cdot \left( \frac{\text{m}} {\text{s}}\right)^2 = \text{kgms}^{-2}](https://tex.z-dn.net/?f=E%20%3D%20mc%5E2%20%5CRightarrow%20%5BE%5D%20%3D%20%5Ctext%7Bkg%7D%20%5Ccdot%20%5Cleft%28%20%5Cfrac%7B%5Ctext%7Bm%7D%7D%20%7B%5Ctext%7Bs%7D%7D%5Cright%29%5E2%20%3D%20%5Ctext%7Bkgms%7D%5E%7B-2%7D)
This can be used also to solve "equations" to prove certain dimensions of unknown constants.