In a dilute acid solution most if not all of the molecules will split into ions.
For example HCl is a strong acid and 100% of the molecules will split into
H+ & Cl-
in a weak acid solution only a portion of the molecules will turn into ions because the ionization percentage isn't as large. Which will essentially leave a high percentage of un-reacted molecules
The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.
Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.
We recognise that
h * 2 = PT - P * h * 20 = 1atm - 0.037atm
= 0.963 atm
1 * h * 2 = Ph * 2V / R * T
= 0.963 atm x 0.520 L / 0.0821 L atm/
molK * 301
= 0.02 mol h2
= 0.02molZn
So 0.02 mol Zn x 65.39 g/mol
= 1.33 g Zn
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N203 is the answer, if i am wrong im sorry!
There are 3 moles of are produced in neutralization when 1. 5 mole of reacts with
The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,
→
from above chemical equation , we can conclude the molar ratio = 1:2
It means two moles of water molecule is produce from one mole of magnesium hydroxide.
So, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles
Therefore, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide is 3 moles.
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