Answer:
The boiling point elevation is 3.53 °C
Explanation:
∆Tb = Kb × m
∆Tb is the boiling point elevation of the solution
Kb is the molal boiling point elevation constant of CCl4 = 5.03 °C/m
m is the molality of the solution is given by moles of solute (C9H8O) divided by mass of solvent (CCl4) in kilogram
Moles of solute = mass/MW =
mass = 92.7 mg = 92.7/1000 = 0.0927 g
MW = 132 g/mol
Moles of solute = 0.0927/132 = 7.02×10^-4 mol
Mass of solvent = 1 g = 1/1000 = 0.001 kg
m = 7.02×10^-4 mol ÷ 0.001 kg = 0.702 mol/kg
∆Tb = 5.03 × 0.702 = 3.53 °C (to 2 decimal places)
One molecule of sucrose is burned with oxygen to make carbon dioxide and water.
Disaccharide sugar sucrose is composed of glucose and fructose. It is produced naturally by plants and is the main component of white sugar. C₁₂H₂₂O₁₁ is the chemical formula for it.
Extraction and refining sucrose for human use can be done from either sugarcane or sugar beet. Raw sugar is created from crushing the cane, which is consistently delivered to other sectors to be refined into pure sucrose. Sugar mills generally are located in the tropical regions near the sugarcane plantations.
<em> C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O</em>
When one molecule of sucrose is burnt, we get 12 carbon dioxide molecules.
To learn more about sucrose,
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Answer:
A = 2A + 3B → 5C
Explanation:
The two molecule of A and three molecules of B will react to form the five molecules of C.
2A + 3B → 5C
Other options are incorrect because,
B = A₂ + B₃ → C₅
in this reaction one molecule of A₂ and one molecule of B₃ combine to form one molecule of C₅.
C = 2A + 5B → 3C
in this reaction two molecules of A and five molecules of B combine to form three molecule of C.
D = A₂ + B₃ → C₃
in this reaction one molecule of A₂ and one molecule of B₃ combine to from one molecule of C₃.
Answer:
Yes
Explanation: Had a question like this and I said yes and got it right
