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3 years ago

10

: 3m -2n + 5m + Zn - 3

1 answer:

dem82 [27]3 years ago

7 0

cevabı lazım lutfenbanada

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5 (x + 2) = 3 (x + 8)

aleksley [76]

So first you distribute the 5 to the x and the +2 and get
5x+10=3(x+8)
then you distribute the 3 to the other x and the +8 and get
5x+10=3x+24
subtract 3x from both sides
2x+10=24
subtract 10 from both sides and get
2x=14
divide both sides by 2 and get
x=7

8 0

3 years ago

Read 2 more answers

What is the value of the expression 5x2 + 2x when x = 5?

masha68 [24]

Answer:

135

Step-by-step explanation:

Given:

$x = 5$

To determine a numerical value for the expression, simply substitute the value of "x" into the expression and simplify the expression, if necessary, to determine a specific number for the expression provided.

$\implies 5x^{2} + 2x$

$\implies 5(5)^{2} + 2(5) \longrightarrow \longrightarrow \longrightarrow (x = 5)$

$\implies 5(5)(5) + 2(5)$

$\implies 125 + 10$

$\implies 135$

Therefore, the value of the expression $5x^{2} + 2x$ when x = 5 is 135.

Learn more about this topic: brainly.com/question/27675691

7 0

2 years ago

Answer the one you would like thank you.

dem82 [27]

Answer: 1.9

Step-by-step explanation:

Question 11

9.88 rounds to 10

5.2 rounds to 5

10/5 = 2

6 0

2 years ago

Ben is 4 times old as ishaan. 6 years ago, Ben was 6 times as old as ishaan <br> How old is Ben now?

SpyIntel [72]

Answer:

60years

Step-by-step explanation:

let Ben age = x

ishaan age = y

Ben is 4 times old as ishaan:

x=4y ..........equation (1)

6 years ago

Ben age = x-6

Ishaan age = y-6

x-6=6(y-6)

x-6=6y-36

x=6y-36+6

x=6y-30..........equation (2)

equating equation(1) and (2)

4y=6y-30

4y-6y=-30

-2y=-30

y=-30/-2=15

substituting the value of y into equation (1)

x=4y

=4*15

=60

Ben age now =60years

7 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

3 years ago