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3 years ago

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Se transmiten ondas transversales en una cuerda tensada orientada sobre el eje x. La función de ondas correspondientes es y= 5.0

0 sen(6.05x + 5.19t + 1.57). Donde y y x están en metros y t en segundos. Cual es la rapidez de las ondas que se transmiten en dicha cuerda?

1 answer:

TEA [102]3 years ago

4 0

Answer:

Explanation:

Whats the entire question?

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Which quantities are vectors

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For example, displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.

Explanation:

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You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a buildin

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3 years ago

A 79.7 kg base runner begins his slide into second base while moving at a speed of 4.77 m/s. The coefficient of friction between

SashulF [63]

To solve this problem we will apply the concept related to the kinetic energy theorem. Said theorem states that the work done by the net force (sum of all forces) applied to a particle is equal to the change experienced by the kinetic energy of that particle. This is:

$\Delta W = \Delta KE$

$\Delta W = \frac{1}{2} mv^2$

Here,

m = mass

v = Velocity

Our values are given as,

$m = 79.7kg$

$v = 4.77m/s$

Replacing,

$\Delta W = \frac{1}{2} (79.7kg)(4.77m/s)^2$

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3 years ago

What is the pressure inside such a balloon (in atm) if it starts out at sea level with a temperature of 12.8°C and rises to an a

tatiyna

Answer:

The final pressure inside the balloon will be $P_2=0.0359\ atm$ .

Explanation:

Given initial temperature of the balloon is $T_1=12.8\°C$

And the final temperature of the balloon is $T_2=-47.7\°C$

Initially, the balloon is at atmospheric pressure $P_1=1\ atm$ and volume be $V_1$

And the final pressure in the balloon is $P_2$ and the volume be $V_2$

Also, it is given in the question that the final volume became twenty-two times the original volume.

We can write $V_2=22V_1$

Now, using ideal gas equation.

$\frac{P_2V_2}{P_1V_1}=\frac{nRT_2}{nRT_2}$

Where, $R$ is the gas constant. And $n$ is moles of substance inside the balloon.

In our problem the value of $n$ will be the same for both cases. Also, $R$ is the gas constant.

$\frac{P_2V_2}{P_1V_1}=\frac{T_2}{T_1}$

Also, we have $V_2=22V_1$ from the question.

$\frac{P_2\times 22V_1}{P_1V_1}=\frac{T_2}{T_1}\\\\\frac{P_2\times 22}{P_1}=\frac{T_2}{T_1}$

We need to convert the temperature from $\°C$ to Kelvin.

$T_1=12.8\°C\\T_1=12.8+273.15=285.95\\T_2=-47.7\°C\\T_2=-47.7+273.15=225.45$

Plug these values we get,

$\frac{P_2\times 22}{1}=\frac{225.45}{285.95}\\\\22\times P_2=0.789\\P_2=\frac{0.789}{22}\\P_2=0.0359\ atm.$

So, the final pressure inside the balloon will be $P_2=0.0359\ atm$ .

6 0

3 years ago

Two plane waves of the same frequency and with vibrations in the z-direction are given by c (y, t) = (2 cm) cos a p 4 cm y - 20

My name is Ann [436]

The resultant wave at point (5, 2) is Ψ = 5.99 cos [ 7.15 - (20/s) t]

What are the plane waves:

A plane wave is a special case of wave or field: whose value, at any moment, is constant through any plane that is perpendicular to a fixed direction in space.
plane waves are free-space modes.

Here,

Two plane waves are given:

c (5, t) = 4 cos [(8π/3) - (20/s) t]

c (2, t) = 2 cos [(3π/2) - (20/s) t]

now, the waves as imaginary exponentials,

separating the spatial parts, and then adding them together

we get The resultant:

Ψ = [ 4 sin (8π/3) + 2 sin (3π/2) ]^2 + [ 4 cos(8/3 π) + 2 cos(3/2π) ]^2

Ψ = 5.99 tan(a) = 0.747/ 5.95

a = 7.15

Ψ = 5.99 cos [ 7.15 - (20/s) t]

hence,

The resultant wave is Ψ = 5.99 cos [ 7.15 - (20/s) t]

Learn more about Resultant wave here:

<u>brainly.com/question/1190546</u>

#SPJ4

Your question is incomplete, but most probably the full question was:

Two plane waves with the same frequency and with vibrations (measured by Psi) in the z-direction are given by c (x, t) = (4cm.) cos [pi/3cm. x - 20/s t + pi] c (y, t) = (2cm.) cos[pi/4cm. y - 20/s t + pi]

Express the waves as imaginary exponentials, separate the spatial parts, and add them together using a phasor diagram to find the resultant at the point x = 5cm. y = 2cm

4 0

2 years ago