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yan [13]
3 years ago
15

The truck travels for 1.5 hours as it makes the 90 mile trip from the warehouse to the store. What was the average speed in mile

s per hour of the truck while driving to deliver the product to the waiting customers?
Physics
1 answer:
andrezito [222]3 years ago
6 0

Answer: 60 mph

Explanation:

Given

Truck takes 1.5\ hr to make 90\ mile trip

The average speed is the ratio of total distance traveled to the total time taken.

v_{avg}=\dfrac{\text{Distance}}{\text{time}}\\\\v_{avg}=\dfrac{90}{1.5}\\v_{avg}=60\ mph

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It takes 130 J of work to compress a certain spring 0.10m. (a) What is the force constant of this spring? (b) To compress the sp
Ede4ka [16]

Explanation:

Given that,

Work done to stretch the spring, W = 130 J

Distance, x = 0.1 m

(a) We know that work done in stretching the spring is as follows :

W=\dfrac{1}{2}kx^2\\\\k=\dfrac{2W}{x^2}\\\\k=\dfrac{2\times 130}{(0.1)^2}\\\\k=26000\ N/m

(b) If additional distance is 0.1 m i.e. x = 0.1 + 0.1 = 0.2 m

So,

W=\dfrac{1}{2}kx^2\\\\W=\dfrac{1}{2}\times 26000\times 0.2^2\\\\W=520\ J

So, the new work is more than 130 J.

6 0
3 years ago
In a double-slit experiment, if the central diffraction peak contains 13 interference fringes, how many fringes are contained wi
Ronch [10]

Answer:

Explanation:

Width of central diffraction peak is given by the following expression

Width of central diffraction peak= 2 λ D/ d₁

where d₁ is width of slit and D is screen distance and λ is wave length.

Width of other fringes become half , that is each of  secondary diffraction fringe is equal to

λ D/ d₁

Width of central interference  peak is given by the following expression

Width of  each of  bright fringe =  λ D/ d₂

where d₂ is width of slit and D is screen distance and λ is wave length.

Now given that the central diffraction peak contains 13 interference fringes

so ( 2 λ D/ d₁)  /  λ  D/ d₂ = 13

then (  λ D/ d₁)  /  λ  D/ d₂ = 13 / 2

= 6.5

no of fringes  contained within each secondary diffraction peak = 6.5

6 0
4 years ago
How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
Superman throws a boulder of weight 3800 n at an adversary on the surface of the earth, where the magnitude of the acceleration
evablogger [386]
The weight of the boulder is 3800 N, therefore its mass i s
3800/9.8 = 387.755 kg

If the horizontal acceleration is 12.8 m/s², then the horizontal force applied is
F = (387.755 kg)*(12.8 m/s²) = 4.963 x 10³ n = 4.963 kN

Answer: 4.963 kN
5 0
4 years ago
A free electron is moving with a velocity of 3 × 105 m/s. It strikes a stationary electron in a head-on elastic collision. The m
Gelneren [198K]

Answer:

After the colision, the stationary electron's momentum is given as:

P = 2.7328 x 10^(-25) kg m/s

The direction of momentum is the same as the direction of velocity of the electron.

Explanation:

In an Isolated system, when an object moving at some velocity v collides head on with a stationary object of equal mass. There velocities are exchanged.

This means that the first electron will become stationary and the electron which was stationary initially will start moving at a velocity of 3*10^(5)m/s in the same direction as the first electron.

Post collision momentum of the stationary electron:

V = 3 x 10^5 m/s

m = 9.1093 x 10^(-31) kg

Momentum = P = mV =  9.1093 x 10^(-31) x 3 x 10^5

P = 2.7328 x 10^(-25) kg m/s

The direction of momentum is the same as the velocity of the electron.

7 0
4 years ago
Read 2 more answers
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