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Vedmedyk [2.9K]
3 years ago
12

A tall flagpole is a harmonic oscillator, flexing back and forth with a steady period. The pole rises from a base that is fixed

in the ground, but you can push it forward from chest height. To increase the amplitude of the pole's motion, you should push it forward when it isA. moving toward you.
B. as close to you as possible.
C. moving away from you.
D. as far from you as possible.
Physics
1 answer:
Alika [10]3 years ago
7 0

Answer:

C. moving away from you.

Explanation:

According to Newton's second law of motion when we multiply the mass of an object and the acceleration that the body is experiencing we get the force applied.

If the flagpole is coming towards me and I push it the velocity of the oscillation will slow as the acceleration would be in the negative direction of the motion

If the flagpole is moving away from me then the acceleration that I provide will be added to the acceleration of the oscillating flagpole which will increase the amplitude.

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What is the difference between rutherford's model of the atom and bohr's model of the atom
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flipper (the dolphin) is out in the open ocean hunting tuna avec. he emits his pulse at 22khz and .42 seconds later he hears it
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First we need to find the speed of the dolphin sound wave in the water. We can use the following relationship between frequency and wavelength of a wave:
v=\lambda f
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v=(0.02 m)(22000 Hz)=440 m/s

We know that the dolphin sound wave takes t=0.42 s to travel to the tuna and back to the dolphin. If we call L the distance between the tuna and the dolphin, the sound wave covers a distance of S=2 L in a time t=0.42 s, so we can write the basic relationship between space, time and velocity for a uniform motion as:
v= \frac{S}{t}= \frac{2L}{t}
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3 years ago
A spearfisher stands in shallow water and sees a fish a few feet in front of her. She throws her spear directly toward the posit
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Answer:

the spear will end up above the fish relative to the actual position of the fish.

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due to refraction of light coming from the fish the fish will appear slightly above from its real position

So due to this refraction the spearfisher will throw the spear directly at the image of the fish due to which it will not reach the position of fish but it will reach the position above the fish.

So here we can say that the spear will end up above the fish relative to the actual position of the fish

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4 years ago
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