A tall flagpole is a harmonic oscillator, flexing back and forth with a steady period. The pole rises from a base that is fixed
1 answer:
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Out of the given options, weight is influenced by mass and gravity
Answer: Option A
<u>Explanation: </u>
The object's mass is defined as the quantity of a matter with which the object is formed. It can change its state of matter but the quantity will remain the same. However, the weight is defined as how much force gravity exerts on the object's mass to pull it.
The mass is always same irrespective the location but the weight may vary from one place to the other while talking for the bigger picture. For example, the object's weight may be 60 kg on Earth but when it is measured on the moon, it will be lesser.
The weight of an object generally has nothing doing with the volume and it doesn't depend solely on the gravitational pull. The mass plays a crucial role.
Answer:
h = 1.8 m
Explanation:
The initial velocity of the glove, u =- 6 m/s
We need to find the maximum height of the glove. Let it is equal to h. Using equation of kinematics. At the maximum height v = 0
, h is the maximum height and a = -g
Hence, it will go up to a height of 1.8 m.
The acceleration of the car is 0.8049.It takes 13.802s to travel the 230 m.
<h3>What is acceleration?</h3>
In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. Newton's Second Law states that the combined effect of two factors determines how much an item accelerates:
(i) It follows that the magnitude of the net balance of all external forces acting on the object is directly proportional to the magnitude of this net resulting force, and
(ii) the mass of the thing, depending on the materials out of which it is constructed, is inversely proportional to the mass of the thing.
Calculations:
40 km/hr ----- 11.11m/s
80 km/hr ----- 22.22m/s
Time taken
v-u=at
22.22-11.11= 0.8049 x t
t=13.802s
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