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Nitella [24]
3 years ago
8

7 Calculate the weight of an apple of mass 100 grams

Physics
1 answer:
Leni [432]3 years ago
4 0

Answer:

See the anwers below

Explanation:

To solve this problem we must understand that the weight of anyW = 0.1*10\\W = 1 [N]body is defined as the product of mass by gravitational acceleration. Gravitational acceleration depends on the place in space where a certain body is located.

W = m*g\\

where:

W = weight [N]

m = mass = 100 [g] = 0.1 [kg]

g = gravity acceleration [m/s²] or [N/kg]

<u>Now for the Earth</u>

<u />W =m*g\\W =0.1*10\\W = 1[N]<u />

<u>For the Moon</u>

<u />W = m*g\\W =0.1*1.6\\W = 0.16 [N]<u />

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An average human weighs about 650 N. If each of two average humans could carry 1.0 C of excess charge, one positive and one nega
bezimeni [28]

Answer:

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans, q_1=q_2=1\ C

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

F=\dfrac{kq^2}{r^2}

r=\sqrt{\dfrac{kq^2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times (1)^2}{650}}

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

5 0
3 years ago
For the different values given for the radius of curvature RRR and speed vvv, rank the magnitude of the force of the roller-coas
nirvana33 [79]

Explanation:

The force of the roller-coaster track on the cart at the bottom is given by :

F=\dfrac{mv^2}{R}, m is mass of roller coaster

Case 1.

R = 60 m v = 16 m/s

F=\dfrac{(16)^2m}{60}=4.26m\ N

Case 2.

R = 15 m v = 8 m/s

F=\dfrac{(8)^2m}{15}=4.26m\ N

Case 3.

R = 30 m v = 4 m/s

F=\dfrac{(4)^2m}{30}=0.54m\ N

Case 4.

R = 45 m v = 4 m/s

F=\dfrac{(4)^2m}{45}=0.36m\ N

Case 5.

R = 30 m v = 16 m/s

F=\dfrac{(16)^2m}{30}=8.54m\ N

Case 6.

R = 15 m v =12 m/s

F=\dfrac{(12)^2m}{15}=9.6m\ N

Ranking from largest to smallest is given by :

F>E>A=B>C>D

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Ram is the son of Seema

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Answer:

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