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Nadya [2.5K]
3 years ago
7

A stone initially moving at 8.0 m/s on a level surface comes to rest due to friction after it travels 11 m. What is the coeffici

ent of kinetic friction between the stone and the surface?
Physics
1 answer:
Ivenika [448]3 years ago
3 0

Answer:

Coefficient of friction will be 0.296

Explanation:

We have given initial speed of the stone u = 8 m /sec

It comes to rest so final speed v = 0 m /sec

Distance traveled before coming to rest s = 11 m

According to third equation of motion

v^2=u^2+2as

So 0^2=8^2+2\times a\times 11

a=\frac{-64}{22}=-2.90m/sec^2

Acceleration due to gravity g=9.8m/sec^2

We know that acceleration is given by

a=\mu g

So 2.90=9.8\times \mu \\

\mu =\frac{2.9}{9.8}=0.296

So coefficient of friction will be 0.296

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