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Natalija [7]
4 years ago
13

A 80.0kg football player running at 12.5 m/s North runs into a 120.kg player running South. The 120.kg player grabs the other on

e so they move together at -4.50m/s. What was the velocity of the 120.kg player?
Physics
1 answer:
Masteriza [31]4 years ago
8 0

Answer:

p=-540kg•m/s

Explanation:

because I used a calc

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A solid block of metal is at its melting temperature. it takes 24j to melt 6kg of a metal. what is the latent heat of fusion of
Marina86 [1]

The Latent heat of fusion is also known as the Enthalpy of Fusion. It is a kind pf change in enthalpy.

<h3>Brief explanation of Latent Heat of Fusion? </h3>

The latent heat of fusion, is the change in enthalpy that takes place when energy, typically heat, is provided to a specific quantity of a substance to causes it to change from a solid state to a liquid state at a constant pressure.

For instance, 1 kilogram of ice melts at 0 °C at a variety of pressures, absorbing 333.55 kJ of energy without causing a change in temperature.

The heat of solidification, which occurs when a substance changes from a liquid to a solid, is equal and opposing.

This energy includes the contribution necessary to displace its surroundings against ambient pressure in order to accommodate any corresponding change in volume.

The melting point or the freezing point, depending on the situation, is the temperature at which the phase transition takes place. Conventionally, unless otherwise stated, the pressure is taken to be 1 atm (101.325 kPa).

<h3>Calculation</h3>

The formula of latent heat of fusion is L= q/m

Here q is the heat provided and m is the mass of the object.

So, L = 24j/6kg

L= 4j/kg

So, the latent heat of fusion is 4 j/kg

To know more about latent Heat of Fusion visit:

brainly.com/question/28044951

#SPJ4

8 0
2 years ago
A motor must lift a 1500-kg elevator cab. The cab's maximum occupant capacity is 400 kg, and its constant "cruising" speed is 1.
natka813 [3]

Answer:

12900 W

24200 W

Explanation:

Given:

v₀ = 0 m/s

v = 1.3 m/s

t = 2.0 s

Find: a and Δx

v = at + v₀

(1.3 m/s) = a (2.0 s) + (0 m/s)

a = 0.65 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (1.3 m/s + 0 m/s) (2.0 s)

Δx = 1.3 m

While accelerating:

Newton's second law:

∑F = ma

F − mg = ma

F = m (g + a)

F = (1500 kg + 400 kg) (9.8 m/s² + 0.65 m/s²)

F = 19855 N

Power = work / time

P = W / t

P = Fd / t

P = (19855 N) (1.3 m) / (2.0 s)

P ≈ 12900 W

At constant speed:

Newton's second law:

∑F = ma

F − mg = 0

F = mg

F = (1500 kg + 400 kg) (9.8 m/s²)

F = 18620 N

Power = work / time

P = W / t

P = Fd / t

P = Fv

P = (18620 N) (1.3 m/s)

P ≈ 24200 W

5 0
4 years ago
25 mL of water is poured into a graduated cylinder. Several coins are dropped into the water, and the new volume is measured to
ra1l [238]
5 cubic cm is the answer
6 0
3 years ago
3. Explain why one side of the single magnet attracted the metal surface, but repelled the stack of magnets
valina [46]

Answer:

Explained

Explanation:

one side of the single magnet attracted the metal surface, but repelled the stack of magnets because  magnet's both poles  try to attract by inducing opposite pole on the metal surface,but the pole closer to the metal is able to induce more magnetic character .so, attractive force due to this is more strong as the distance is also less as compared to the other pole.

7 0
3 years ago
Read 2 more answers
A 45 g bullet strikes and becomes embedded in a 1.55 kg block of wood placed on a horizontal surface just in front of the gun. I
zimovet [89]

Answer:

299.51 m/s

Explanation:

m = mass of the bullet = 45 g = 0.045 kg

M = mass of the block = 1.55 kg

v = muzzle speed of the bullet

V = speed of bullet-block combination after the collision

μ = Coefficient of friction between the block and the surface = 0.28

d = distance traveled by the block = 13 m

V' = final speed of the bullet-block combination = 0 m/s

acceleration of the bullet-block combination due to frictional force is given as

a = - μg

using the kinematics equation

V'² = V² + 2 a d

0² = V² + 2 (- μg) d

0 = V² - 2 (μg) d

0 = V² - 2 (0.28) (9.8) (13)

V = 8.45 m/s

Using conservation of momentum for collision between bullet and block

mv = (M + m) V

(0.045) v = (1.55 + 0.045) (8.45)

v = 299.51 m/s

6 0
3 years ago
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