I think it’s -0.75. The x coordinate represents the term number so y would show the pattern which is -3.75, -4.5, -5.25, -6, -6.75, -7.5, -8.25, -9. To get to the next number, each term is being decreased by 0.75. Hope this helps :)
Answer:
1) b and m
2) m∠8=m∠6
3) 160°
4)x=60°
Step-by-step explanation:
1) all straight lines sum to 180°
subtract the angles given from 180°
the other angle for b is 25°, while the other angle for m is 155°
so we can see that the angles for both lines are the same, hence they are parallel.
2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4
in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.
3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°
(2x-16)°+(7x+20)°=180°
we get x=20(nearest whole number)
∠CED=7x+20=7(20)+20=160°
4) since we need to show that they are parallel,
(2x+30)°=(4x-90)°
2x-4x=-90-30
-2x=-120
x=60
we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)
I hope u understand it the way I put it.
Yes rational numbers are equal to integers.
Answer:
2211.68123
Step-by-step explanation:
Using the formula to find volume of cylinder
V=πr2h=π·82·11≈2211.68123
Answer:
500 boxes
Step-by-step explanation:
<em>hey there,</em>
<em />
< Since "p" stands for profits, change "p" to 0 (since the question says 0 profits).
Here is how your equation would look like:
Pretend like "n" is "x" since that is the variable we are trying to find here.
Solve for "n". Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
"n" actually ends up equaling 500, -200.
Obviously, negative can't be the answer because you can't have a negative amount of boxes. So 500 boxes would be your answer. 200 CAN'T be your answer <em>either </em>because it is a negative!! >
<u>Hope this helped! Feel free to ask anything else.</u>
