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Ann [662]
3 years ago
8

For some jobs, “good enough” is good enough. That’s sometimes true in chemistry. More often, though, careful planning, calculati

ons, measurement, and laboratory work are necessary to get the desired result. Imagine two tasks that would involve a chemical reaction of some sort. For one, measurement is not all that critical. For the other, careful stoichiometry and laboratory process is essential. Identify and describe two tasks (projects, operations, devices, etc.) that differ in this way.
Chemistry
1 answer:
Rasek [7]3 years ago
7 0

One is: vinegar and baking soda volcano. But a more planned, complicated experiment, would be a nuclear energy program.

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Answer:

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Explanation:

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Four moles of Argon gas are at a pressure of 1.90 atm, and the temperature is 50 degrees C. What is the volume of the gas?
soldier1979 [14.2K]
N = 4 moles of Ar2, P = 1.90 atm, V = ?
T = 50C = 273 + 50K = 323K
PV = nRT --> V = nRT/P
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Answer:

Newton's 1st law,

Explanation:

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Consider the following unbalanced redox reaction:
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Mn04 is being reduced
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The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut
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Answer:

Molarity=1.22\ M

Explanation:

Given:  

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (19 + 273.15) K = 292.15 K  

Volume = 0.200 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K  

⇒n = 0.008174 moles

From the reaction shown below:-

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

1 mole of H_2SO_4 react with 2 moles of NaOH

0.008174 mole of H_2SO_4 react with 2*0.008174 moles of NaOH

Moles of NaOH = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.016348}{0.0134}\ M

Molarity=1.22\ M

8 0
3 years ago
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