The standard unit for measuring mass is the blank

You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y

lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 6 days

a = initial amount of the reactant = 1 g

a - x = amount left after decay process = 0.2 g

a) to find the rate constant

$6=\frac{2.303}{k}\log\frac{1.0}{0.2}$

$k=\frac{2.303}{6}\log\frac{1.0}{0.2}$

$k=0.268days^{-1}$

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days$

The half life is 2.58 days

3 0

3 years ago

Identify what kind of ligand (weak or strong), what kind of wavelength (long or short), what kind of spin (high spin or low spin

anzhelika [568]

To find - Identify what kind of ligand (weak or strong), what kind

of wavelength (long or short), what kind of spin (high spin or

low spin) and whether it is paramagnetic or diamagnetic for

the following complexes.

1. [Mn(CN)6]4-

2. [Fe(OH)(H2O)5]2

3. [CrCl4Br2]3-

Step - by - Step Explanation -

1.

[Mn(CN)⁶]⁴⁻ :

Ligand - Strong

Wavelength - Short

Spin - Low spin

Number of unpaired electrons = 1 ∴ paramagnetic.

2.

[Fe(OH)(H₂O)₅]²⁺ :

Ligand - Weak ( both OH⁻ and H₂O )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 5 ∴ paramagnetic.

3.

[CrCl₄Br₂]³⁻ :

Ligand - Weak ( both Br⁻ and Cl⁻ )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 3 ∴ paramagnetic.

7 0

2 years ago

Need help with this question plsssss

GaryK [48]

Answer:

234

Explanation:

8 0

2 years ago

What is the name of P517

saul85 [17]

Answer:

Ryobi P517 18V Lithium Ion Cordless Brushless 2,900 SPM Reciprocating Saw w/ Anti-Vibration Handle and Tool-Less Blade Changing

Explanation:

8 0

3 years ago

The solubility of N2 in blood at 37°C and a partial pressure of 0.80 atm is 5.6 ✕ 10−4 mol·L−1. A deep-sea diver breathes compre

marysya [2.9K]

Answer:

0.0126 moles are released

Explanation:

Using Henry's law, where the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid:

S = k×P

Where S is solubility (5.6x10⁻⁴molL⁻¹), k is Henry's constant and P is partial pressure (0.80atm)

Replacing:

5.6x10⁻⁴molL⁻¹ / 0.80atm = 7x10⁻⁴molL⁻¹atm⁻¹

Thus, with Henry's constant, solubility of N₂ when partial pressure is 3.8atm is:

S = 7x10⁻⁴molL⁻¹atm⁻¹ × 3.8atm

S = 2.66x10⁻³molL⁻¹

Thus, when the deepd-sea diver has a pressure of 3.8amt, moles dissolved are:

6.0L × 2.66x10⁻³molL⁻¹ = 0.01596 moles of N₂

At the surface, pressure is 0.80atm and solubility is 5.6x10⁻⁴molL⁻¹, moles dissolved are:

6.0L × 5.6x10⁻⁴molL⁻¹ = 3.36x10⁻³mol

Thus, released moles are:

0.01596mol - 3.36x10⁻³mol = 0.0126 moles are released

8 0

3 years ago