Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The question is to determine the simplest mass ratio of gold to Chlorine in the compound.
Since the mass of gold in the compound compared to chlorine is 15.39 g for every 2.77 g, the mass of gold per gram of chlorine is given as:
15.39 / 2.77 = 5.56 g of gold to two decimal places
<em>Therefore, for every 5.56 g of gold, there is 1 g of chlorine.</em>
<em>Note : The ratio in which different elements combine by mass to form a compound is given by the law of constant composition which states that, "all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.</em>
NO.OF.MOLES= MASS/ATOMIC MASS
THE ATOMICITY OF SULPHUR IS 8 AND ITS MASS NUMBER IS 32.
SO, THE ATOMIC MASS IS 256
NO.OF.MOLES= 53.7/256
= 537/2560
= 0.2097
A. 0.02 mol of O2
B. 0.1 mol of CI2
C. 1 mol of N2
D. 2 mol of H2
Bolded answer is correct.
No of Neutrons =Mass No-No of protons
- Hence it has atomic no 38
The element is Stroncium(Sr)
