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olga nikolaevna [1]
3 years ago
9

Using the first volume and pressure reading on the table as V1 and P1, solve for the unknown values in the table below. Remember

to use the rules of significant figures when entering your numeric response.

Chemistry
1 answer:
maw [93]3 years ago
8 0
Hope this helps. I provided step by step in the picture below if you want to see how I got these answers.
A= 1.0L
B= 0.50atm
C= 0.60atm
D= 4.0L

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What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol
ad-work [718]

Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 63 g * 1 mol/(58.44 g)

moles of NaCl = 1.078 moles

Finally we can find the molarity of the solution

molarity = moles of NaCl/(volume of solution)

molarity = 1.078 moles/(0.65 L)

molarity = 1.66 M

Answer: the molarity of the solution is 1.66 M.

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1 year ago
Why are a molecule's atoms as far away from each other as they can get?
Olenka [21]

Answer: A

Explanation:

Because I just answered it and it’s right. ( Forces between electron pairs push the atoms apart.

6 0
3 years ago
Why does the pressure inside a container of gas increase?
yan [13]
Pressure is a scientific parameter that allows us to determine the amount of force being exerted per unit area. The increase in the pressure inside a container containing a gas may be brought upon by the decrease in volume, increase in temperature, or merely by additional of more gas molecules. 
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Problem PageQuestion Gaseous ethane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of w
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Answer:

<h2> = ( 1.08 / 2.2 ) 100% = 49%</h2>

Explanation:

Balanced Equation: 2CH₃CH₃(g) + 5O₂(g) → 2CO₂(g) + 6H₂O(g)

Calculate moles of CH₃CH₃ and O₂

1.2 ₃₃ ( 1 ₃₃/ 30.0694 ₃₃ ) = 0.040 ₃₃

8.6 ₂ ( 1 2/ 31.998 ₂ ) = 0.27 ₃₃

Find limiting reagent  0.040 ₃₃ ( 5 ₂/ 2 ₃₃ ) = 0.10 ₂

CH₃CH₃ is the limiting Reagent

CH₃CH₃ (L.R.) O₂ CO₂ H₂O

Initial (mol) 0.040 0.27 0 0

Change (mol) -2x=-0 -5x= -0.10  +2x=+0.040 +6x=+0.12

Final (mol) 0 0.117 0.040 0.12

0.040 − 2 = 0 = 0.020

Determine percent yield

0.12 ₂ ( 18.0148 ₂ /1 ₂ ) = 2.2 ₂  

= ( 1.08 / 2.2 ) 100% = 49%

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How many moles of hydrogen<br> are in 3.7 moles of C8H11 NO2?
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40.7 because I know
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2 years ago
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