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Anna11 [10]
3 years ago
5

A speed skater goes around a turn with a 31 m radius. The skater has a speed of 14 m/s and experiences a centripetal force of 46

0 N. What is the mass of the skater?
Physics
1 answer:
dybincka [34]3 years ago
4 0

Answer:

Mass of the skater, m = 72.75 kg

Explanation:

It is given that,

Radius of the circular path, r = 31 m

Speed of the skater, v = 14 m/s

Centripetal force, F = 460 N

We need to find the mass of the skater. It can be determined using the formula of centripetal force. It is given by :

F=\dfrac{mv^2}{r}

m=\dfrac{Fr}{v^2}

m=\dfrac{460\ N\times 31\ m}{(14\ m/s)^2}

m = 72.75 kg

So, the mass of the skater is 72.75 kg. Hence, this is the required solution.

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A third baseman makes a throw to first base 40.5 m away. The ball leaves his hand with a speed of 30.0 m/s at a height of 1.4 m
Ugo [173]

Answer:

When the ball goes to first base it will be 4.23 m high.

Explanation:

Horizontal velocity = 30 cos17.3 = 28.64 m/s

   Horizontal displacement = 40.5 m

   Time  

         t=\frac{40.5}{28.64}=1.41s          

   Time to reach the goal posts 40.5 m away = 1.41 seconds

Vertical velocity = 30 sin17.3 = 8.92 m/s

    Time to reach the goal posts 40.5 m away = 1.41 seconds

    Acceleration = -9.81m/s²

    Substituting in s = ut + 0.5at²

             s = 8.92 x 1.41 - 0.5 x 9.81 x 1.41²= 2.83 m

    Height of throw = 1.4 m

    Height traveled by ball = 2.83 m

    Total height = 2.83 + 1.4 = 4.23 m

    When the ball goes to first base it will be 4.23 m high.

8 0
3 years ago
A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th
krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, \lambda=145\ m

If f is the frequency of the wave. The frequency of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz

The time period of the wave is given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

T=\dfrac{8.92}{2}\\\\T=4.46\ s

Hence, this is the required solution.

5 0
3 years ago
Mangrove forests play an important role in _______.
AysviL [449]
D. All of the above

At high tide fish will feed among the mangrove roots - rich fishing ground

The trees trap sediment and soil in the river that would flow out to sea which also helps stop erosion

Wildlife utilise almost every part of the tree, with insects and birds, monkeys and lizards in the branches, shrimps and fish in the roots, and snails and clams in the soil
4 0
2 years ago
Why a body in uniform velocity is zero acceleration ?​
seropon [69]
Uniform velocity means no Net force and therefore no acceleration. Acceleration only happens when the velocity changes.
4 0
3 years ago
The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an
Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

   \Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t

or,      \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

Putting the given values into the above formula as follows.

    \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

                = \frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}    

                = 0.326 rad/s^{2}

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 rad/s^{2}.

5 0
3 years ago
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