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Anna11 [10]
4 years ago
5

A speed skater goes around a turn with a 31 m radius. The skater has a speed of 14 m/s and experiences a centripetal force of 46

0 N. What is the mass of the skater?
Physics
1 answer:
dybincka [34]4 years ago
4 0

Answer:

Mass of the skater, m = 72.75 kg

Explanation:

It is given that,

Radius of the circular path, r = 31 m

Speed of the skater, v = 14 m/s

Centripetal force, F = 460 N

We need to find the mass of the skater. It can be determined using the formula of centripetal force. It is given by :

F=\dfrac{mv^2}{r}

m=\dfrac{Fr}{v^2}

m=\dfrac{460\ N\times 31\ m}{(14\ m/s)^2}

m = 72.75 kg

So, the mass of the skater is 72.75 kg. Hence, this is the required solution.

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3 0
4 years ago
The construction of a flat rectangular roof (6.17 m × 5.92 m) allows it to withstand a maximum net outward force of 2.00 × 104 N
Blababa [14]

Answer:

v_2=29.13\ m/s

Explanation:

It is given that,

Dimension of the rectangular roof, (6.17 m × 5.92 m)

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The density of air, \rho=1.29\ kg/m^3

The Bernoulli equation is used to find wind speed of this roof blow outward. It is given by :

P_1+\dfrac{1}{2}\rho v_1^2=P_2+\dfrac{1}{2}\rho v_2^2

Here, v_1=0 (since air inside the roof is not moving)

v_2=\sqrt{\dfrac{2(P_1-P_2)}{\rho}}

Since, F=(P_1-P_2)A

v_2=\sqrt{\dfrac{2F}{\rho A}}

v_2=\sqrt{\dfrac{2\times 2\times 10^4}{1.29\times 6.17\times 5.92 }}

v_2=29.13\ m/s

So, the wind speed of  this roof blow outward is 29.13 m/s. Hence, this is the required solution.

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4 years ago
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