Answer:
The initial arrow's velocity is 40,9 m/s at 11.9° from the horizontal
Explanation:
<em>In order to find the inital velocity we need to determine its components and the angle that the arrow is launched at.</em>
<em>For horizontal component, we will have:</em>
<em>ν cos(θ)t = x ⇒ cos(θ) = x/νt</em>
<em>For vertical component we will have:</em>
<em>h= v sin(θ)t ₋ gt²÷ 2 ⇒ sin (θ) = h + gt²÷2/νt</em>
<em>From the two equations we got, after noting that the vertical displacement is 3m, we can calculate </em>
<em>tan(θ) = h +gt²÷2/νt/ x÷νt = h+ gt²÷2/x = 3+ 9.8.0.5²÷2/20 = 0.21125</em>
<em>Now we can calculate θ = tan⁻¹(0.21125) ≈ 11.9°</em>
<em>Now that we know the angle we can subtitute at any of the expressions for the two components of the velocity . Let's do this subsitution at the horizontal component:</em>
<em>ν cos(θ)t= x =ν = x/tcos(θ)= 20/ 0.5cos(11.9) ≈ 40.9 m/s.</em>
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Answer:
Explanation:
Assuming that h is much smaller than R, then we can say the acceleration of gravity is approximately constant.
Potential energy = Kinetic energy
mgh = 1/2 mv²
v = √(2gh)
v = √(2 (MG/R²) h)
v = √(2 MGh) / R
Subductions occur at convergent boundaries. Its where one tectonic plate moves under another.
-Steel jelly
Answer:
Force between the two charges becomes one fourth of the initial force.
Explanation:
The electrostatic force acting between any two charges is given as,
Here,
F = force
k = Coulomb's constant
= magnitude of charge of the first particle
= magnitude of charge of the second particle
= separation between the two charges
From the above relation,
Thus,
