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Paladinen [302]
2 years ago
6

Question 7

Chemistry
1 answer:
Taya2010 [7]2 years ago
8 0

Answer:

Carbon has an atomic number of 6. That means a carbon atom has 6 protons, 6 neutrons, and 6 electrons.

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What is the molecular formula of each compound?<br> (c) Empirical formula HgCl (m = 5 472.1 g/mol)
beks73 [17]

The molecular formula of HgCl (m = 5 472.1 g/mol) is Hg2Cl4.

The molecular formula is an expression that defines the number of atoms of each element in one molecule of a compound. It shows the actual number of each atom in a molecule.

<h3>Molecular formula: What is it?</h3>

A chemical formula is a way to communicate information in chemistry about the proportions of atoms that make up a specific chemical compound or molecule. Chemical element symbols, numbers, and occasionally other symbols like parentheses, dashes, brackets, commas, and plus and minus signs are used to represent the chemical elements.

A molecule's molecular formula reveals which atoms and how many of each kind are included within it. No subscript is used if there is just one atom of a certain kind. A subscript is added to the symbol for an atom if it contains two or more of a certain type of atom.

To learn more about molecular formula visit:

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4 0
2 years ago
Really strong acids and bases are found at the​
makkiz [27]

Ends....................?

4 0
3 years ago
Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
Andru [333]

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

3 0
3 years ago
What happens when magnesium reacts with iodine to make magnesium iodide?
I am Lyosha [343]

Explanation:

Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. On the other hand, atomic number of iodine is 53 and its electronic configuration is [Kr]4d^{10}5s^{2}5p^{5}.

Hence, there are 7 valence electrons in an iodine atom and there are 2 valence electrons in a magnesium atom.

So, one atom of iodine requires one electron from a donor atom to complete its octet. But one magnesium atom contains two valence electrons.

Therefore, one magnesium atom will combine with two iodine atoms to result in the formation of magnesium iodide as follows.  

            Mg^{2+} + 2I^{-} \rightarrow MgI_{2}

Therefore, an ionic bond will be formed when  magnesium reacts with iodine to make magnesium iodide.

7 0
4 years ago
What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?
Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is O_{2} molecule.

Solution : Given,

Mass of methane = 23 g

Molar mass of methane = 16.04 g/mole

The Net balanced chemical reaction for combustion of methane is,

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

First we have to calculate the moles of methane.

\text{ Moles of methane}=\frac{\text{ Given mass of methane}}{\text{ Molar mass of methane}} = \frac{23g}{16.04g/mole} = 1.434 moles

From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give \frac{2moles\times 1.434moles}{1moles} moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is O_{2} molecule.


6 0
3 years ago
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