9514 1404 393
Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
__
<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
__
<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.
Answer:
Step-by-step explanation:
Given 
a)
we know that 
therefore 
on integrating we get
c=(1/6640)
b)
on doing the integration we get
=0.37349
c)
marginal density of X is
on doing integration we get
f(x)=(4x+3)/3320 ; 0<x<40
marginal density of Y is
on doing integration we get
d)
solve the above integration we get the answer
e)
solve the above integration we get the answer
f)
Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.
we know f(x,y)
In the (c) bit we got f(x) and f(y)
f(x,y)cramster-equation-2006112927536330036287f(x).f(y)
therefore X and Y are not independent
Answer:
5280people
Step-by-step explanation:
Given parameters:
Percentage increase of population = 25%
Population now = 6600
Unknown:
Population last year = ?
Solution:
Let the population last year = y;
Then;
Percentage of last years population plus the population of last year should give us this year's population;
(
of y) + y = 6600
0.25y + y = 6600
1.25y = 6600
y =
= 5280people
Last year, there was 5280people in the locality.
Answer:

Step-by-step explanation:
1 = ¼[8] + b
2

* Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so −4 becomes ¼.
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