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dezoksy [38]
3 years ago
5

2. Moving ocean water exerts a force of 375 N on a boat, causing the boat to move a distance of 34.7 m in 8.34 s. What power doe

s the boat produce in kW?
Knowns Unknown

d = ________________ t = _________________ P = ?

F = ________________
Solve for the Unknown (Use the definition of Power)

Physics
1 answer:
sasho [114]3 years ago
8 0
1.56 kW , working shown in photo

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Which of the following best describes the velocity of an object
max2010maxim [7]
The definition of volocity is <span>the speed of something in a given direction.</span>
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A metal can containing condensed mushroom soup has mass 215 g, height 10.8 cm, and diameter 6.38 cm. It is placed at rest on its
s344n2d4d5 [400]

Answer:

Part a)

Moment of inertia of the cylinder is given as

I = 1.21 \times 10^{-4} kg m^2

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as I = 1/2 mR^2

Explanation:

As we know that the inclined plane is of length L = 3 m

and its inclination is given as 25 degree

so we know that acceleration of center of mass of the cylinder is constant so we will have

v_f^2 = v_i^2 + 2 a L

so we have

v_f^2 = 0 + 2a(3)

now we know that

v_{avg} = \frac{L}{t} = \frac{v_f + v_i}{2}

\frac{3}{1.50} = \frac{v_f + 0}{2}

v_f = 4 m/s

Now we have know that final speed of the cylinder due to pure rolling is given as

v_f = \sqrt{\frac{2gH}{1 + \frac{I}{mR^2}}}

4 = \sqrt{\frac{2(9.81)(3 sin25)}{1 + \frac{I}{0.215(0.0319)^2}}}

I = 1.21 \times 10^[-4} kg m^2

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as I = 1/2 mR^2

8 0
2 years ago
An engineer weighs a sample of mercury (ρ = 13.6 × 103 kg/m3 ) and finds that the weight of the sample is 6.0 n. what is the sam
Amanda [17]
Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.

Let V =  the volume of the sample.
Then
W = ρVg
or
V =  W/(ρg)
   = (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
   = 4.4972 x 10⁻⁵ m³

Answer: The volume is 44.972 x 10⁻⁶ m³
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A kayak on a lake is moving at a constant speed of 2.4 m/s in a direction 41.2° north of west. After 27 min, find the following.
xeze [42]

Answer:

b

Explanation:

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