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dezoksy [38]
4 years ago
5

2. Moving ocean water exerts a force of 375 N on a boat, causing the boat to move a distance of 34.7 m in 8.34 s. What power doe

s the boat produce in kW?
Knowns Unknown

d = ________________ t = _________________ P = ?

F = ________________
Solve for the Unknown (Use the definition of Power)

Physics
1 answer:
sasho [114]4 years ago
8 0
1.56 kW , working shown in photo

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Physics class 9 chapter 8 please tell​ please
natali 33 [55]

Answer:

(a) The motion is uniform

(b)  11.11 m/s

Explanation:

(a)

From the table below, the motion of the bus is uniform.

(b)

Speed(s) = Δd/Δt

s = Δd/Δt............. Equation 1

From the table,

Given: Δd = 10 km = 10000 m, Δt = 15 minutes = (15×60) = 900 seconds

Substitute these values into equation 1

s = 10000/900

s = 11.11 m/s

7 0
3 years ago
A man works on a striaght road from his home to market 2.5km away dwith a speed of 5km/h.Finding the market closed, he instantly
umka21 [38]

Answer:

5.625km/h

Explanation:

We are given that

Distance between home and market, d=2.5 km

Speed, v1=5km/h

Speed, v2=7.5 km/h

We have to find the average speed of the man over the interval of time 0 to 40min.

Time,t=\frac{distance}{speed}

Using the formula

t_1=\frac{2.5}{5}=0.5 h=0.5\times 60=30 min

1 hour =60 min

t_2=\frac{2.5}{7.5}=\frac{1}{3}hour=\frac{60}{3}=20min

Distance traveled by man in 10 min with speed 7.5 km/h=\frac{2.5}{20}\times 10=2.5/2km

Therefore,

Total distance covered=2.5+2.5/2=3.75 km

Time=40 min=40/60=2/3 hour

Average speed=\frac{total\;distance}{total\;time}

Average speed=\frac{3.75}{2/3}=5.625km/h

7 0
3 years ago
A 1,250 kg car is moving due to 6,500 N engine force. If the kinetic friction coefficient between the car and the road is 0.32,
Yuliya22 [10]

Answer:

b i hope this is correct answee

7 0
3 years ago
In an open system, such as a campfire, matter can?
-Dominant- [34]
I am positive with my and answer and i think yes
7 0
3 years ago
A farmhand pushes a 23 kg bale of hay 3.9 m across the floor of a barn. If she exerts a horizontal force of 91 N on the hay, how
uranmaximum [27]

Answer:

W = 354.9 J

Explanation:

Given that,

The mass of a bale of hay, m = 23 kg

The displacement, d = 3.9 m

The horizontal force exerted on the hay, F = 91 N

We need to find the work done. We know that,

We know that,

Work done, W = Fd

So,

W = 91 N × 3.9 m

W = 354.9 J

So, the required work done is 354.9 J.

4 0
3 years ago
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