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Allushta [10]
3 years ago
7

. A student thinks that the more protons an atom has, the more reactive it will be. Which will best disprove this student's idea

?
Compare the reactivities of lithium (Li) and krypton (Kr).
Note that rubidium has 48 neutrons.
Compare the number of protons in cesium (Ce) and xenon (Xe).
Count the number of neutrons in an atom of helium.
Physics
1 answer:
shepuryov [24]3 years ago
6 0
The best answer to the question that is being stated above would be the first choice. To disprove the claims of the student that you need more protons to have more reactivity, then you proceed to compare the reactivities of lithium (Li) and krypton (Kr). Krypton has more protons than Lithium, but it is less reactive because it is a noble gas.
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Which option gives an object's volume in Sl units?
Phoenix [80]

Answer:

B.

Explanation:

K is the SI unit for Kelvin which measures temperature.

kg is NOT an SI unit, g is the SI unit for mass.

L is NOT an SI unit, m^3 is the SI unit for volume.

Therefore the answer is B.

3 0
3 years ago
The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be
kap26 [50]

Answer:

v = 14.86 m/s

Explanation:

As we know that the force equation at the top is given as

\frac{mv^2}{R} = ma

now we know that

a_c = 1.5 g

so we have

\frac{v^2}{R} = 1.5 g

v = \sqrt{1.5 Rg}

so we will have

v = \sqrt{1.5(15)(9.81)}

v = 14.86 m/s

3 0
3 years ago
What is the mass of a bicycle that has 90 kg.m/s of momentum at a speed of 6 m/s?
OLEGan [10]

Answer:

m = 15 kg

Explanation:

p = m × v

90 = m × 6

6m = 90

m = 90/6

m = 15 kg

6 0
2 years ago
A star produces 2x10^26 watts. how much energy does it lose every minutes
Step2247 [10]

Answer:

Energy loss per minute will be 120\times 10^{26}j

Explanation:

We have given the star produces power of 2\times 10^{26}W

We know that 1 W = 1 J/sec

So 2\times 10^{26}W=2\times 10^{26}J/sec

Given time = 1 minute = 60 sec

So the energy loss per minute =2\times 10^{26}\times 60=120\times 10^{26}j

We multiply with 60 we have to calculate energy loss per minute

7 0
3 years ago
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0
3 years ago
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