Relate a real life phenomenon with each branch of physics
1 answer:
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Answer:
103.5 meters
Explanation:
Given that a stunt person has to jump from a bridge and land on a boat in the water 22.5 m below. The boat is cruising at a constant velocity of 48.3 m/s towards the bridge. The stunt person will jump up at 6.45 m/s as they leave the bridge.
The time the person will jump to a certain spot under the bridge can be calculated by using the formula below:
h = Ut + 1/2gt^2
since the person will fall under gravity, g = 9.8 m/s^2
Also, let assume that the person jump from rest, then, U = 0
Substitute h, U and g into the formula above
22.5 = 1/2 * 9.8 * t^2
22.5 = 4.9t^2
22.5 = 4.9t^2
t^2 = 22.5/4.9
t^2 = 4.59
t =
t = 2.143 seconds
From definition of speed,
speed = distance /time
Given that the boat is cruising at a constant velocity of 48.3 m/s towards the bridge, substitute the speed and the time to get the distance.
48.3 = distance / 2.143
distance = 48.3 * 2.143
distance = 103.5 m
Therefore, the boat should be 103.5m away from the bridge at the moment the stunt person jumps?
<u>Answer:</u>
Below!
<u>Explanation:</u>
Referring to the picture, we can conclude that the picture J will have the most effect on ocean tides.
Whichever model is similar to model J in the picture will be your answer.
Hoped this helped.
Answer:
The final speed is 9.89 m/s.
Explanation:
Initial speed of skydiver is 0 as it was rest.
Acceleration of the skydiver is 9.8 m/s²
It accelerates for the first 5 m of their fall.
It is required to find their final speed. Let v is the final speed. It can be calculated using third equation of motion.
Here, u = 0
a = 9.8 m/s²
s = 5 m
So, the final speed is 9.89 m/s.