Answer:
ε= 7.86 mV, Current: Anti-clockwise
Explanation:
radius= 50 mm
dt= 0.10 s
Initial magnitude of magnetic field= B1 = 200 mT
Final magnitude of magnetic field = B2 = 300 mT
Ф= B. A= BA cosα
Ф1= B1 * A * cosα
Ф1=
Ф1= 0.00157 Wb
Ф2= B2 * A * cosα
Ф1=
Ф2=0.00236 Wb
dФ= Ф2 - Ф1
dФ= 0.00236 - 0.00157
dФ= 0.000786 Wb
ε= Ф
ε=0.001786/ 0.10
ε=0.00786 v = 7.86 mV
b)
According to lenz's law the induced emf always oppose the cause producing it.
Applied field is out of the paper so the current will flow in anti-clockwise direction to produce north pole pointing toward the paper.
Answer:
s = 50.4 m
Hence, the point C is 50.4 m towards east from point B
Explanation:
Since, the motorcyclist travels at a constant speed in straight line towards east after point B. Therefore, we can use the following equation in this case:
s = vt
where,
s = distance covered = position of point C = ?
v = uniform speed of motorcyclist = 18 m/s
t = time interval = 2.8 s
Therefore,
s = (18 m/s)(2.8 s)
<u>s = 50.4 m</u>
<u>Hence, the point C is 50.4 m towards east from point B</u>
7200 joules of heat and light energy was dissipated into the air. But no work was done ... no force moved through no distance.
Answer:
5.4 × 10⁸ W/m²
Explanation:
Given that:
The Power (P) of Betelgeuse is estimated to release 3.846 × 10³¹ W
the mass of the exoplanet = 5.972 × 10²⁴ kg
radius of the earth = 1.27 × 10⁷ m
half the distance (i.e radius r ) = 7.5 × 10¹⁰ m
a) What is the intensity of Betelgeuse at the "earth’s" surface?
The Intensity of Betelgeuse can be determined by using the formula:
I = 544097698.8 W/m²
I = 5.4 × 10⁸ W/m²
Answer:
h = 2.49 [m]
Explanation:
In order to solve this problem we must use the definition of potential energy, which tells us that energy is equal to the product of mass by gravity by height.
The potential energy can be calculated by means of this equation:
Ep = m*g*h
where:
Ep = potential energy = 980 [J]
m = mass = 40 [kg]
g = gravity acceleration = 9.81 [m/s^2]
h = elevation [m]
Now replacing:
980 = 40*9.81*h
h = 2.49 [m]