Answer:
a) 4.98m/s²
b) 481.66N
Explanation:
a) Using the Newtons second law of motion
m is the mass of the object
g is the acceleration due to gravity
Fm is the moving force acting along the plane
Ff is the frictional force opposing the moving froce
a is the acceleration of the skier
Given
m = 60kg
g = 9.8m/s²
= 35°
Ff = 38.5N
Required
acceleration of the skier a
Substituting into the formula;
Hence the acceleration of the skier is 4.98m/s²
b) The normal force on the skier is expressed as;
N = Wcosθ
N = mgcosθ
N = 60(9.8)cos 35°
N = 588cos 35°
N = 481.66N
Hence the normal force on the skier is 481.66N
<h2>Answer:</h2>
<u>Distance covered is 6.9 meters</u>
<h2>Explanation:</h2>
Data given:
Work Done = 345 kJ = 345000 J
Force = 5 x 10 ^ 4 = 50000 N
Distance = ?
Solution:
As we know that
Work Done = Force applied x Distance covered
By arranging the equation we get
Work / Force = Distance covered
By putting the values
345000 / 50000 = 6.9
So distance covered is 6.9 meters
solution;
given
- speed of wave= frequency×wavelength
=460×18
= 8280m/s
Explanation:
<h2>first of all given should be written & by using the formula of speed of sound .</h2>
Answer:
S1 = 1/2 g t^2 distance stone falls in time t
S2 = Vy t - 1/2 g t^2 distance thrown stone rises in time t
H = 49 = S1 + S2 = Vy t
t = 49 / 40 sec time when stones meet
Check:
Stone 1 falls: 1/2 g t^2 = 1/2 * 9.8 * (49 / 40)^2 = 7.35 m
Stone 2 rises : 40 * (49 / 40) - 1/2 * 9.8 (49 / 40)^2 = 41.65 m
