Write an expression to evaluate the relative error in g (given that g= 2h/t^2) in terms of h,Δh,t,Δt

A uniform meter stick (with a length of 1.00 meter) has a mass of 108 g. It is supported at its midpoint by a vertical rigid blu

alexandr1967 [171]

Answer:4

Explanation:

Given

$m_1=21\ gm$

$m_2=27\ gm$

Mass of stick is $m=108\ gm$

Let T be the tension in the red string

Now if the red string is cut , suppose T is the tension in the blue rod immediately after cut

Therefore

$T=m_1g+m_2g$

$T=(0.021+0.027)\times 10$

$T=0.48\ N$

4 0

3 years ago

A plane is flying to Minnesota with a velocity of 277.73 km/h, N. The plane

umka2103 [35]

Answer:

466 km/h

255°

measured anticlockwise from the east direction

Explanation:

find the resultant velocity of a plane after a crosswind affects its motion. take the positive

x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are

upx = 0
upy = 450 Km/ h

And for the wind.

uwx = - 120 Km/h
uwy = 0

The components for the resultant velocity of the plane are given by

ux =upx + uwx = 0 - 120 Km/h = - 120 Km/h

uy = upy + uwy = - 450 Km/h +0 = - 450 Km/h

The magnitude of the resultant velocity is

$\sqrt{(vx)^2+(vy)^2} =\sqrt{(-120lkm/h^2+(-450lkm/h)^2}$

= 466 km/h

Hope this helps u : )

7 0

1 year ago

What two forces are there when you skydive

dusya [7]

Gravity is pulling you down and friction is slowing you down so you don't plummet to the ground at super high speeds.

7 0

3 years ago

Read 2 more answers

Three dogs (Spot, Fido, and Steinberg) are pulling on a chew toy. The chew toy is experiencing no acceleration. Spot is pulling

quester [9]

Answer:

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

Explanation:

The chew toy is at equilibrium and experimenting three forces from three distinct dogs. The Free Body Diagram depicting the system is attached below. By Newton's Laws we construct the following equations of equilibrium: (Sp is for Spot, F is for Fido and St is for Steinberg) All forces and angles are measured in newtons and sexagesimal degrees, respectively:

$\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0$ (1)

$\Sigma F_{y} = F_{F}\cdot \sin \theta_{F}-F_{Sp}+F_{St,y} = 0$ (2)

If we know that $F_{F} = 20\,N$ , $F_{Sp} = 30\,N$ and $\theta_{F} = 63^{\circ}$ , then the components of the force done by Steinberg on the chewing toy is:

$F_{St,x} = -F_{F}\cdot \cos \theta_{F}$

$F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}$

$F_{St, x} = -9.080\,N$

$F_{St,y} = F_{Sp}-F_{F}\cdot \sin \theta_{F}$

$F_{St,y} = 30\,N-(20\,N)\cdot \sin 63^{\circ}$

$F_{St, y} = 12.180\,N$

The magnitud of the force is determined by Pythagorean Theorem:

$F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}$

$F_{St} =\sqrt{(-9.080\,N)^{2}+(12.180\,N)^{2}}$

$F_{St} \approx 15.192\,N$

Since the direction of this force is in the 3rd Quadrant on Cartesian plane, we determine the direction of the force with respect to the eastern semiaxis:

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)$

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{12.180\,N}{-9.080\,N}\right)$

$\theta_{St} \approx 126.704^{\circ}$

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

5 0

3 years ago

Why should you explore the potential roadblocks to your chosen career?

valina [46]

Answer: D

Explanation: D is the most reasonable answer because it's always good to plan ahead for anything, so if you were to plan ahead for future obstacles, then you can overcome them.

6 0

3 years ago