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Stells [14]
2 years ago
5

HEMP ME ITS DUE BY MIDNIGHT ​

Chemistry
2 answers:
balu736 [363]2 years ago
8 0

Answer:

Explanation:

Option B is the correct answer

MissTica2 years ago
8 0
Option b for sure because it is the correct answer and I know
You might be interested in
What causes objects to speed up, slow down, and change directions?
vlada-n [284]
The answer is force

sorry if i’m wrong
4 0
3 years ago
Consider the following reaction:C2H4(g) + F2(g) -----------> C2H4F2(g) Delta H = -549 kJEstimate the carbon-fluorine bond ene
frutty [35]

Answer:

Bond energy of carbon-fluorine bond is 485 kJ/mol

Explanation:

Enthalpy change for a reaction,  is given as:

\Delta H_{rxn}=\sum [n_{i}\times (E_{bond})_{i}]-\sum [n_{j}\times (E_{bond})_{j}]

Where (E_{bond})_{i}  and (E_{bond})_{j} represents average bond energy in breaking "i" th bond and forming "j" th bond respectively.n_{i} and n_{j} are number of moles of bond break and form respectively.

In this reaction, one mol of C=C, four moles of C-H and one mol of F-F bonds are broken. One mol of C-C bond, four moles of C-H bonds and two moles of C-F bonds are formed

So, -549kJ=(1mol\times 614kJ/mo)+(4mol\times E_{C-H})+(1mol\times 154kJ/mol)-(1mol\times 347kJ/mol)-(4mol\times E_{C-H})-(2mol\times E_{C-F})

or, -549kJ=(1mol\times 614kJ/mo)+(1mol\times 154kJ/mol)-(1mol\times 347kJ/mol)-(2mol\times E_{C-F})

or, E_{C-F}=485kJ/mol

So bond energy of carbon-fluorine bond is 485 kJ/mol

8 0
3 years ago
A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul
WITCHER [35]
Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
 
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

                                        P1*v1/T1 =  P2*v2/T2
As, the temperature is constant;
 So,
                                               v1/T1 = v2/T2
                                              417/278 = v2/231
                                                  v2= 346.5 cm³                                           
5 0
3 years ago
25 points! Help please
Sedbober [7]

Answer:

I think its b

Explanation:

but I wouldn't depend on this answer

4 0
3 years ago
Read 2 more answers
How much water should be added to 4.3 moles of LiBr to prepare a 2.05 m solution?
arsen [322]

Answer:

2.1 kg of water

Explanation:

Step 1: Given data

  • Moles of lithium bromide (solute): 4.3 moles
  • Molality of the solution (m): 2.05 m (2.05 mol/kg)
  • Mass of water (solvent): ?

Step 2: Calculate the mass of water required

Molality is equal to the moles of solute divided by the kilograms of solvent.

m = moles of solute/kilograms of solvent

kilograms of solvent = moles of solute/m

kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg

8 0
2 years ago
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