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artcher [175]
3 years ago
14

Suppose an electron in some atom absorbs energy and transitions from level 1 up to level 4. Which of the following is a true sta

tement regarding the electron transitions back down to level 1?
Physics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

The transition from energy level 4 to energy level 2, followed by a transition from energy level 2 to 1, is possible. This is because transitioning from a higher level to lower level can be done various ways. In other words transitions in the downward direction can be any number of levels.

Explanation:

It is easier to make transition from higher levels to lower levels because emitting some amount of energy which depends on the the energy level the electron is transitioning to. Unlike downward transitions, the energy level an electron can transition to is limited by the amount of energy made available to it for absorbtion. That is, the amount of energy required to excite it to that state or energy level.

Thank you for reading.

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An electron moves at 2.40×106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.1
Stells [14]

Answer:

a) F = 2.7 10⁻¹⁴ N , b)  a = 2.97 10¹⁶ m / s²  c) θ = 14º

Explanation:

The magnetic force on the electron is given by the expression

     F = q v x B

Which can be written in the form of magnitude and the angle found by the rule of the right hand

     F = q v B sin θ

where θ is the angle between the velocity and the magnetic field

a) the maximum magnitude of the force occurs when the velocity and the field are perpendicular, therefore, without 90 = 1

     F = e v B

     F = 1.6 10⁻¹⁹ 2.40 10⁶ 7.10 10⁻²

     F = 2.73 10⁻¹⁴ N

     F = 2.7 10⁻¹⁴ N

b) Let's use Newton's second law

    F = m a

    a = F / m

    a = 2.7 10⁻¹⁴ / 9.1 10⁻³¹

    a = 2.97 10¹⁶ m / s²

The actual acceleration (a1) is a quarter of this maximum

    a1 = ¼ a

    a1 = 7.4 10¹⁵ m / s²

With this acceleration I calculate the force that is executed on the electron

     F = ma

    e v b sin θ= ma

    sin θ = ma / (e v B)

    sin θ = 9.1 10⁻³¹ 7.4 10¹⁵ / (1.6 10⁻¹⁹ 2.40 10⁶ 7.10 10⁻²)

    sin θ = 6.734 10⁻¹⁵ / 27.26 10⁻¹⁵

    sin θ = 0.2470

    θ = 14.3º

4 0
4 years ago
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