Uno:
El dióxido de Carson (CO2)
Answer:
Chiral:
3-Methyl-2-butanol
Achiral:
1-Pentanol
3-Pentanol
3-Methyl-1-butanol
Explanation:
Only the molecule that bears a carbon atom surrounded by 4 different groups can be said to be Chiral, the other molecules don't satisfy this property.
Answer:
Wavelength of the first four spectral line:
Explanation:
Lman series when electron from higher shell number and jumps to 1st shell then all the possible lines is called as lyman series.
to calculate wavelength of first four spectral line:
For hydrogen Z=1;
by using rydberg equation
![\frac{1}{\lambda} =RZ^2[\frac{1}{n_1^2} -\frac{1}{n_2^2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3DRZ%5E2%5B%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%5Cfrac%7B1%7D%7Bn_2%5E2%7D%20%5D)
1. n=2 to n=1
=rydberg constant
2. n=3 to n=1
3. n=4 to n=1
4. n=5 to n=1
This is an exception to the general electronegativity trend. It can be explained by looking at the electron configurations of both elements.
<span>Be:[He]2<span>s2
</span></span><span>B:[He]2<span>s2</span>2<span>p1
</span></span>
When you remove an electron from beryllium, you are taking away an electron from the 2s orbital. When you remove an electron from boron, you are taking an electron from the 2p orbital. The 2p electrons have more energy than the 2s, so it is easier to remove them as they can more strongly resist the effective nuclear charge of the nucleus.
