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vladimir1956 [14]
3 years ago
14

2. Write the chemical equations for the neutralization reactions that occurred when HCL and NaOH were added to the buffer soluti

on.
Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

Explanation:

A buffer is a solution that resists changes in acidity or alkalinity. A buffer is able to neutralize a little amount of acid or base thereby maintaining the pH of the system at a steady value.

A buffer may be an aqueous solution of a weak acid and its conjugate base or a weak base and its conjugate acid.

The equations for the neutralizations that occurred upon addition of HCl or NaOH are;

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

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3 years ago
Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C
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The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

<em>"Your question is not complete, it seems to be missing the following information;"</em>

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

  • <em>mass of water, </em>m_w<em> = 45 g</em>
  • <em>final temperature of the water, </em>t_w<em> = 22 ⁰C</em>
  • <em>mass of the metal, m = 8.5 g</em>
  • <em>initial temperature of the metal, t = 82 ⁰C.</em>
  • <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

<em>heat gained by water = heat lost by metal</em>

Q_{water} = Q_{metal}

m_wc_w \Delta t_w = mc\Delta t

where;

c_w <em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>

<em />

<em>Substitute the given values;</em>

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16  - 188.28t = 240.98

188.28t  = 4142.16  - 240.98

188.28t  = 3901.18

t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

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