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enyata [817]
2 years ago
14

A balloon is filled with 35.0 L of helium in the morning when the temperature is 35.00 oC.

Chemistry
1 answer:
nexus9112 [7]2 years ago
5 0

Answer: V = 33.9 L

Explanation: We will use Charles Law to solve for the new volume.

Charles Law is expressed in the following formula. Temperatures must be converted in Kelvin.

V1 / T1 = V2 / T2 then derive for V2

V2 = V1 T2 / T1

= 35 L ( 308 K ) / 318 K

= 33.9 L

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

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P₂ = second pressure

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V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

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Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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