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3 years ago

A car travels a distance of 540km in 6 hours. What speed did it travel at?

Physics

2 answers:

maria [59]2 years ago

4 0

Speed v = distance travelled / time taken

v = d / t

v = 540 / 60h

v = 9 km /h

const2013 [10]2 years ago

4 0

The speed of the car that travels a distance of 540km in 6 hours is 90km/hr

Explanation:

Given:

Distance the car travels =540km

Time taken by the car to travel 540 km= 6 hours

To Find:

Rate at which the car travels=?

Solution:

$\text { formula for speed }=\frac{\text { distance }}{\text { time }}$

Substituting the known values,

$\text { formula for speed }=\frac{\text {distance}}{\text {time}}$

$\text { formula for speed }=\frac{540}{6}$

$\text { formula for speed }=90 \mathrm{km} / \mathrm{hr}$

Thus the speed of car is $90 \mathrm{km} / \mathrm{hr}$

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A sound wave with a frequency of 400 Hz is moving through a solid object. If the wavelength of the sound wave is 8 m, what is th

Paraphin [41]

Answer:

v = 3200 m/s

Explanation:

As we know that the frequency of the sound wave is given as

$f = 400 Hz$

wavelength of the sound wave is given as

$\lambda = 8 m$

so now we have

$speed = wavelength \times frequency$

so we will have

$v = (8m) \times (400 Hz)$

$v = 3200 m/s$

4 0

3 years ago

A 295-kg object and a 595-kg object are separated by 4.10 m.

kodGreya [7K]

Answer:

a)F=3 x 10⁻⁷ N

b)x=2.405 m

Explanation:

Given that

m₁=295 kg

m₂=595 kg

d= 4.1 m

m₃=63 kg

r=d/2 = 2.05 m

The force between the mass m₁ and m₃

$F_{13}=\dfrac{Gm_1m_3}{r^2}$

by putting the values

$F_{13}=\dfrac{Gm_1m_3}{r^2}$

$F_{13}=\dfrac{6.67\times 10^{-11}\times 295\times 63 }{2.05^2}$

F₁₃=2.94 x 10⁻⁷ N

The force between the mass m₂ and m₃

by putting the values

$F_{23}=\dfrac{Gm_2m_3}{r^2}$

$F_{23}=\dfrac{6.67\times 10^{-11}\times 595\times 63 }{2.05^2}$

F₂₃=5.94 x 10⁻⁷ N

The net force F

F= F₂₃- F₁₃

F=5.94 x 10⁻⁷ N-2.94 x 10⁻⁷ N

F=3 x 10⁻⁷ N

Lest take at distance x from mass m₂ net force is zero.

$F_{23}=\dfrac{Gm_2m_3}{x^2}$

$F_{13}=\dfrac{Gm_1m_3}{(4.1-x)^2}$

Form above two equation

$\dfrac{Gm_1m_3}{(4.1-x)^2}=\dfrac{Gm_2m_3}{x^2}$

$\dfrac{m_1}{(4.1-x)^2}=\dfrac{m_2}{x^2}$

$\dfrac{295}{(4.1-x)^2}=\dfrac{595}{x^2}$

x²=2.01(4.1-x)²

x=1.42 (4.1-x)

x=5.82 - 1.42x

x=2.405 m

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2 years ago

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2 years ago

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A student sees a newspaper ad for an apartment that has 1730 square feet (ft2) of floor space. How many square meters of area ar

SVETLANKA909090 [29]

The correct answer for this question is 160.89 m².

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We know that one square foot equals 0.093 square meters.

We can determine the area in square meters using the above conversion.

Total square meters = 0.093×1730ft² (or) 1730÷10.7

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1 year ago

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lbvjy [14]

Answer:

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Explanation:

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2 years ago

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