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ch4aika [34]
2 years ago
13

you read in an astronomy book that our milky way galaxy consists of about 200 billion stars. how do you suppose this number was

determined?
Physics
1 answer:
lapo4ka [179]2 years ago
6 0

By utilizing a galaxy model that accurately explains all of the data that has been collected thus far.

<h3>Suppose it turns out that one in 1 million stars has a planet that at some point in its history is home to an advanced civilization. Then the total number of civilizations that have arisen in our galaxy would be closest to _____. Assume there are about 100 billion stars in the Milky Way galaxy.</h3>

It has been estimated that our galaxy has something close to 100,000 different civilizations.A galaxy is a collection of stars (or solar systems), gas, and dust that is located in a certain area of the universe.

It has been suggested that the Milky Way, the galaxy in which we reside, is replete with extinct civilizations.In conclusion, there are probably close to 100,000 civilizations in our galaxy as a whole.

To learn more about Milky Way Galaxy , visit :

brainly.com/question/27555211

#SPJ4

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In order to place a satellite into orbit, it requires enough fuel to supply the necessary mechanical energy. Into what types of
nexus9112 [7]

When a satellite is revolving into the orbit around a planet then we can say

net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have

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A 8.2-V battery is connected in series with a 38-mH inductor, a 150-Ω resistor, and an open switch.A 8.2-V battery is connected
tigry1 [53]

Answer:

(A). The current in the circuit is 19.25 mA.

(B). The store energy in the inductor is 7.04 μJ.

Explanation:

Given that,

Voltage = 8.2 V

Inductor = 38 mH

Resistance = 150 Ω

Time t = 0.110 ms

The battery has negligible internal resistance, so that the total resistance  in the circuit is 150 ohms. Then use this equation for current at time t in terms of inductance

We need to calculate the current

Using formula of current

I(t)=\dfrac{V}{R}\times(1-e^{-t\times\dfrac{R}{L}})

Put the value into the formula

I(t)=\dfrac{8.2}{150}\times(1-e^{-0.110\times10^{-3}\times\dfrac{150}{38\times10^{-3}}})

I(t)=0.01925\ A

I(t) = 19.25\ mA

(B). We need to calculate the store energy in the inductor

Using formula of energy

E=\dfrac{1}{2}LI^2

Put the value into the formula

E=\dfrac{1}{2}\times38\times10^{-3}\times(0.01925)^2

E=7.04\times10^{-6}\ J

{tex]E=7.04\ \mu J[/tex]

Hence, (A). The current in the circuit is 19.25 mA.

(B). The store energy in the inductor is 7.04 μJ.

8 0
3 years ago
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