All categories

3 years ago

Find the mass of a football player who's momentum is 630 kg•m/s backward and. is traveling at 7 m/s.

Physics

1 answer:

Setler [38]3 years ago

5 0

Answer:

<h2>The answer is 90 kg</h2>

Explanation:

In order to find the mass of the football we use the formula

$m = \frac{p}{v} \\$

where

p is the momentum

v is the velocity

We have

$m = \frac{630}{7} \\$

We have the final answer as

Hope this helps you

You might be interested in

Two clowns are launched from the same spring-loaded circus cannon with the spring compressed the same distance each time. Clown

sweet-ann [11.9K]

Answer:

the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.

Explanation:

Let the spring constant of the spring is k.

For clown A:

m = 40 kg

let the extension in the spring is y.

So, the spring force, F = k y

m g = k y

40 x g = k x y

y = 40 x g / k ..... (1)

For clown B:

m' = 60 kg

Let the extension in the spring is y'.

So, the spring force, F' = k y'

m' g = k y'

y' = 60 x g / k .....(2)

Kinetic energy for A, K = 1/2 ky^2

Kinetic energy for B, K' = 1/2 ky'^2

So, K/K' = y^2/y'^2 K / K' = (40 x 40) / (60 x 60) (from equation (1) and (2))

K / K' = 0.444

K = 0.444 K'

So the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.

5 0

3 years ago

A block slides forward 4.73 m while being pulled back by a 39.7 N force at 142° from the direction of motion. How much work does

lubasha [3.4K]

Answer:

work done by the force, W = -147.97 J

Given:

displacement of the box, s = 4.73 m

angle between force and displacement, $\theta = 142^{\circ}$

Force, F = 39.7 N

Solution:

Work done by the force can be expressed as the dot product of Force, F and displacement 's' is given by:

W = Fscos $\theta$

W = 39.7 $\times 4.73\times cos142^{\circ}$

W = -147.97 J

where negative sign indicates that work is done on the block

6 0

3 years ago

Two forces of magnitudes 4.0 Newtons and 3.0 Newtons pull on a box. The forces make an angle of 40° with each other. What is the

leonid [27]

Answer:

6.6 N

Explanation:

Let's take the direction of the force of 4.0 N as positive x-direction. This means that the force of 3.0 N is at 40 degrees above it. So the components of the two forces along the x- and y-directions are:

$F_{1x} = 4.0 N\\F_{1y} = 0$

$F_{2x} = 3.0 N cos 40^{\circ}=2.3 N\\F_{2y} = 3.0 N sin 40^{\circ} = 1.9 N$

So the resultant has components

$F_x = F_{1x}+F_{2x}=4.0 N +2.3 N = 6.3 N\\F_y = F_{1y} + F_{2y} = 0 + 1.9 N = 1.9 N$

So the magnitude of the resultant is

$F=\sqrt{F_x^2 +F_y^2}=\sqrt{(6.3)^2+(1.9)^2}=6.6 N$

And in order for the body to be balanced, the third force must be equal and opposite (in direction) to this force: so, the magnitude of the third force must be 6.6 N.

3 0

3 years ago

Two objects of masses m1 and m2, with m1 < m2, have equal kinetic energy. How do the magnitudes of their momenta compare

slavikrds [6]

Answer:

every name on here is physics whyyyy but anyways happy news yr eve

Explanation:

6 0

2 years ago

reviews the approach taken in problems such as this one. A bird watcher meanders through the woods, walking 0.916 km due east, 0

Verizon [17]

Answer:

Displacement: 2.230 km Average velocity: 1.274 $\frac{km}{h}$

Explanation:

Let's represent displacement by the letter S and the displacement in direction 49.7° as A. Displaement is a vector, so we need to decompose all the bird's displacement into their X-Y compoments. Let's go one by one:

0.916 km due east is an horizontal direction and cane be seen as direction towards the negative side of X-axis.

0.928 km due south is a vertical direction and can be seen as a direction towards the negative side of Y-axis.
3.52 km in a direction of 49.7° has components on X and Y axes. It is necessary to break it down using trigonometry,

First of all. We need to sum all the X components and all the Y componets.

∑ $Sx = Ax -0.916$ ⇒ ∑ $Sx = [tex]3.52cos(49.7) - 0.916$