Because the temperature remains constant, we can apply Boyle's Law which states that
pV = constant
where
p = pressure
V = volume
Define the two states of the gas.
State 1
Pressure = p₁
Volume = 1000 ml
State 2
Pressure = p₂
Volume = 500 ml
Apply Boyle's law.
1000p₁ = 500p₂
2 = p₂/p₁
By halving the volume, the pressure doubles.
Answer:
The pressure increases by a factor of 2.
The answer for this question is Control Variable because it doesn’t change throughout the experiment.
Answer:
995.12 N/C
Explanation:
R = 9 cm = 0.09 m
σ = 9 nC/m^2 = 9 x 10^-9 C/m^2
r = 9.1 cm = 0.091 m
q = σ x 4π R² = 9 x 10^-9 x 4 x 3.14 x 0.09 x 0.09 = 9.156 x 10^-10 C
E = kq / r^2
E = ( 9 x 10^9 x 9.156 x 10^-10) / (0.091 x 0.091)
E = 995.12 N/C
