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Sladkaya [172]
2 years ago
13

Generic sugar which costs $2.23/kg is made by combining brand X sugar which costs $1.18/kg with brand Y sugar which costs $3.98/

kg. Find the number of kg of brand X sugar and brand Y sugar required to make 40 kg of generic sugar.
Mathematics
1 answer:
White raven [17]2 years ago
5 0

Answer:

X = 14 kg

Y= 7 kg

Step-by-step explanation:

LET  X and Y equal the amounts of brand X and Y

X = kg of brand X

Y = kg of brand Y

we know:

1)   X    +    Y   =   21    (kg)

2)   1X  +   4Y  =   2(X + Y)        (This is the cost/kg * amounts for total cost)  

Coefficients 1,4,2  are the cost/kg)

substitute eq. 1 (X+Y), = 21 into right side of equation 2

1X + 4Y = (21)*2

use elimination to solve 2 equations

X   +   Y = 21

X   + 4Y = 42        (now subtract,       note:  I wrote the 1X as just X)

------------------

0     -3Y  = -21       OR   Y = 7 kg   so X = (21-7) OR   X = 14 kg

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~~~ 30 POINTS ~~~
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<span>1)   3x-2=x+10


</span><span>Now, lets solve this step-by-step.
</span><span>
3x - 2 = x + 10
-x             -x
</span><span>
</span><span>3x - x = 2x                                2x - 2 = 10
</span><span>
</span><span>2x - 2 = 10
</span>2x - 2+2 = 10+2          The inverse operation helps isolate the variable. 
<span>
2x = 12

2x/2 = 12/2

x = 12/2
x = 6</span><span>

Answer: x = 6

2) x + 4 = 19 - 2x </span>

We can solve this much faster

x + 4 = 19 - 2x
                  +2x

x+2x = 3x

3x + 4 = 19
      -4     -4

19-4 = 15

3x= 15
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x= 5

Answer: x = 5

3) 
<span>8x - 20 = x + 15

Much faster now!!

8x - 20 = x + 15
               -x
8x-x = 7x

7x - 20 = 15
      +20   +20
15+20 = 35

7x = 35
7x/7 = 35/7
x = 35/7
x = 5

Answer: x= 5</span>
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3 years ago
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