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m_a_m_a [10]
3 years ago
14

Rank the following molecules from highest to lowest boiling point: CO2, H2S, NaF, NH3. Explain your ranking using IMF’s.

Chemistry
1 answer:
qaws [65]3 years ago
8 0

Answer:

NaF>NH3>H2S>CO2

Explanation:

The boiling point of a substance depends on the magnitude of electronegativity difference and the type of bond between the atoms of the compound in question.

NaF is an ionic substance. Ionic substances have a high melting and boiling point due to the fact that the ionic lattice contains a large number of ions. This means that a lot of energy is usually required to overcome this ion-ion interaction therefore ionic compounds usually have high melting and boiling points.

Nitrogen is more electronegative than sulphur hence NH3 is more polar than H2S and consequently NH3 has a higher boiling point than H2S due to stronger dipole-dipole interaction.

CO2 is a nonpolar molecule hence it has the lowest boiling point. Only weak dispersion forces exist in CO2.

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3 years ago
When 5.58g H2 react by the following balanced equation, 32.8g H2O are formed. What is the percent yield of the reaction? 2H2(g)+
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Answer:

D) 65.7%

Explanation:

Based on the reaction:

2H2(g)+O2(g)⟶2H2O(l)

<em>2 moles of hydrogen produce 2 moles of water assuming an excess of oxygen.</em>

<em />

To find percent yield of the reaction we need to find theoretical yield (The yield assuming all hydrogen reacts producing water). With theoretical yield and actual yield (32.8g H₂O) we can determine percent yield as 100 times the ratio between actual yield and theoretical yield.

<em>Theoretical yield:</em>

Moles of 5.58g H₂:

5.58g H₂ ₓ (1 mol / 2.016g) = 2.768 moles H₂

As 2 moles of H₂ produce 2 moles of H₂O, if all hydrogen reacts will produce 2.768 moles H₂O. In grams:

2.768 moles H₂O ₓ (18.015g / mol) =

49.86g H₂O is theoretical yield

<em>Percent yield:</em>

Percent yield = Actual yield / Theoretical yield ₓ 100

32.8g H₂O / 49.86g ₓ 100 =

65.7% is percent yield of the reaction

<h3>D) 65.7% </h3>

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what are the orbitals present in the fifth principal energy level​

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