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stiks02 [169]
3 years ago
14

All substances are composed of which type of matter

Chemistry
2 answers:
ss7ja [257]3 years ago
8 0
Elements or atoms depending on the options, but I would guess atoms.

Oxana [17]3 years ago
5 0

Answer: All substances are composed of elements.

Explanation: Matter is anything which has mass and occupies space.

The substances can be made up element alone like Helium (He).

They can be made up of molecules of elements also like hydrogen (H_2)

They can also be made up of molecules of compounds like carbon dioxide (CO_2)

They can be made up of mixtures like salt solution in water.

Since all the mixtures, compounds and molecules consists of elements. Therefore, all the substances are composed of elements.

You might be interested in
how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0
3 years ago
Help whats the answer
vesna_86 [32]

Answer:

I would make the replacement parts with the 3D printer to help fix the well

Explanation:

(

6 0
2 years ago
Which of the following statement(s) is/are consistent with the Bohr theory of the atom (and no other)?
olganol [36]

Answer:

(2) The lowest energy orbits are those closest to the nucleus.  

Explanation:

In the Bohr theory  the electrons describe circular orbits around the nucleus of the atom without radiating energy, therefore to maintain the circular orbit, the force that the electron experiences, that is, the coulombian force due to the presence of the nucleus, must be equal to the centripetal force.

The electron only emits or absorbs energy in the jumps from one allowed orbit to another, with only one jump occurring at a time, from layer K (n = 1) to layer L (n = 2),  without going through intermediate orbits. In said change it emits or absorbs a photon whose energy is the difference in energy between both levels.

In Bohr's model, it is stipulated that the energy of the electron is greater the greater the radius r, so the lowest energy orbits are those closest to the nucleus.

5 0
3 years ago
2. A flask and stopper have a mass of 110.525 g. A 50.0-mL sample of gasoline is transferred to the flask, and the flask, stoppe
Dominik [7]

Answer:

  0.690 g/mL

Explanation:

Density is the ratio of mass to volume:

  gasoline mass = (flask+gas mass) - (flask mass) = 145.028 g -110.525 g

  gasoline mass = 34.503 g

Density = (gas mass)/(gas volume) = (34.503 g)/(50.0 mL)

Density = 0.690 g/mL

_____

The least-precise number in this calculation is the sample volume, which has 3 significant figures. Thus, the answer is good only to 3 significant figures.

8 0
3 years ago
Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol)
Yuri [45]

The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal

How to determine the mole of glucose

Mass of glucose = 49 g

Molar mass of glucose = 180.2 g/mol

Mole of glucose = ?

Mole = mass / molar mass

Mole of glucose = 49 / 180.2

Mole of glucose = 0.272 mole

How to determine the energy released

C₆H₁₂O₆ →2C₂H₆O + 2CO₂  ΔH = -16 kcal/mol

From the balanced equation above,

1 mole of glucose released -16 kcal of energy

Therefore,

0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal

Thus, -4.4 Kcal were released from the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

6 0
1 year ago
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