<h2>
Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s</h2>
Explanation:
In horizontal direction there is acceleration or deceleration for a ball tossed upward at an initial angle of 43° off the ground.
So the horizontal component of velocity always remains the same.
Horizontal component of velocity is the cosine component of velocity.
Initial velocity, u = 10 m/s
Angle, θ = 43°
Horizontal component of velocity = u cosθ
Horizontal component of velocity = 10 cos43
Horizontal component of velocity = 7.31 m/s
Since the horizontal velocity is unaffected, we have
Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s
A because it only has one electron in the outer shell.
Answer:
MT disc I = 2,752 10-3 kg m²
MB disc I = 2,726 10⁻³ kg m²
Explanation:
The moment of inertia given by the expression
I = ∫ r² dm
for bodies with high symmetry it is tabulated
for a hollow disk it is
I = ½ M (R₁² + R₂²)
let's apply this equation to our case
disc MT = 1,357 kg
I = ½ 1,357 (0.0079² + 0.0632²)
I = 2,752 10-3 kg m²
disk MB = 1,344 kg
I = ½ 1,344 (0.0079² + 0.0632²)
I = 2,726 10⁻³ kg m²
Answer:
C. 100
D.3
E. 33.3
Explanation:
C. Mechanical Advantage=Load / Effort
= 200N
--------
100N
Therefore,. = 100
D. I. Velocity Ratio= distance moved by the effort / distance moved by load
= 30cm/10cm
= 3
II. Efficiency= M.A / V.R
= 100/3
= 33.33
Answer:
An atomic nucleus is positively charged because it is composed of protons.
Explanation:
Protons are positively charged
Neutrons are neutral
Electrons are negatively charged
