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natka813 [3]
3 years ago
11

What is carbon dioxide?

Physics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

Carbon dioxide is a acid.

Explanation:

Carbon dioxide is an acidic colorless gas with a density about 53% higher than that of dry air. Carbon dioxide molecules consist of a carbon atom covalently double bonded to two oxygen atoms. It occurs naturally in Earth's atmosphere as a trace gas

Bezzdna [24]3 years ago
4 0

Answer:

acidic colorless gas

Explanation:

Carbon dioxide is an acidic colorless gas with a density of about 53% higher than that of dry air. Carbon dioxide molecules consist of a carbon atom covalently double bonded to two oxygen atoms. It occurs naturally in Earth's atmosphere as a trace gas.

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What effect does atmospheric pressure have on density?
Ivanshal [37]

Answer:sometimes it commits to how it will happen

Explanation:

4 0
3 years ago
Read 2 more answers
A company designed and sells an ultrasonic​ receiver, which detects sounds unable to be heard by the human ear. The receiver can
Kruka [31]

Answer:

the diameter of the outside edge of the receiver is 8\sqrt{18} \ \ \ inches

Explanation:

From the schematic free body diagram illustrating what the question is all about below;

Let represent A to be the vertex where the receiver is being placed

S to be the focus

BP to be equal to r (i.e radius of the outer edge)

BC to be 2 r   (i.e the diameter)

Given that AS = 4 in and AP is 18 in

Let AP be x- axis and AY be y -axis

A=(0,0)

S=(4,0) = (0,0)

So that the equation of the parabolic path of the receiver will be:

y^2 =4 ax  \\ \\ y^2 = 4*4*x \\ \\ y^2 = 16x

B = (AP, BP)

B = (18, r)

B lies  y² = 16 x

r² = 16 x

r² 16 × 18

r = \sqrt{16*18 } \\ \\ r = 4\sqrt{18}

Diameter BC = 2r

2* 4\sqrt{18} \\ \\= 8\sqrt{18 }  \ \ \ inches

6 0
4 years ago
Un caballo parte del reposo y alcanza una velocidad de 15m/s en un tiempo de 8s. ¿ Cuál fue su aceleración y que distancia recor
Lemur [1.5K]

Answer: A 120 metros por segundo

Explanation: multiplicas la velocidad por el tiempo

7 0
3 years ago
A 14-kg object moving with a constant velocity
natta225 [31]

The final velocity of the 14 kg object is 1.6 m/s in the same direction

Explanation:

We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 14 kg is the mass of the first object

u_1 = 5.0 m/s is the initial velocity of the first object

v_1 is the final velocity of the first object

m_2 = 8.0 kg is the mass of the second object

u_2 = 3.0 m/s is the initial velocity of the second object

v_2 = 9.0 m/s is the final velocity of the second object

Re-arranging the equation and substituting the values, we find:

v_1 = \frac{m_1 u_1 + m_2 u_2 - m_2 v_2}{m_1}=\frac{(14)(5.0)+(8.0)(3.0)-(8.0)(9.0)}{14}=1.6 m/s

And the direction is the same as the initial direction, since it has the same sign.

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

4 0
3 years ago
Pls help
Arte-miy333 [17]

Answer:

sorry I dont now the answer bro i am so sorry xd ;'(

4 0
3 years ago
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