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3 years ago

If an object absorbs all colors but red, we see

1 answer:

8 0

[I researched for you, since I am not in that particular level to know that knowledge yet. I assure this is accurate info :)]

The answer is A, red.
"Remember, the color you see is light REFLECTING off the surface of that object. If all colors are absorbed in to the surface EXCEPT red, red must be reflected, and you'll see red." - Yahoo User @Chap

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Which statement about velocity is true?

LekaFEV [45]

Answer:

Velocity has both speed and direction. Speed is constant. ... Speed is measured over time.

Explanation:

8 0

3 years ago

In what sense is the earth a closed system?

I am Lyosha [343]

Answer:D

Explanation: just D.)

4 0

3 years ago

Read 2 more answers

A Doppler radar sends a pulse at

Rufina [12.5K]

Answer:

Explanation:

The problem is based on the concept of Doppler's effect of em wave .

Expression for apparent frequency can be given as follows

n = N x (V - v ) / ( V + v )

n is apparent frequency , N is real frequency , V is velocity of light and v is velocity of cloud.

n = 6 x 10⁹ ( 3 x 10⁸ - 8.52 ) / ( 3 x 10⁸ + 8.52 )

= 6 x 10⁹ ( 3 x 10⁸ ) ( 3 x 10⁸ + 8.52 )⁻¹

= 6 x 10⁹ ( 3 x 10⁸ ) ( 3 x 10⁸)⁻¹ ( 1 + 8.52/3 x 10⁸ )⁻¹

= 6 x 10⁹ ( 1 - 8.52/3 x 10⁸ )

= 6 x 10⁹ - 6 x 10⁹x 8.52/ (3 x 10⁸ )

= 6 x 10⁹ 1 - 170 .

So change in frequency = 170 approx.

7 0

3 years ago

Read 2 more answers

You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track to a height o

irina [24]

Answer: 20.765 m/s

Explanation:

This problem can be solved by the conservation of energy principle, this means the initial energy $E_{o}$ must be equal to the final energy $E_{f}$ :

$E_{o}=E_{f}$ (1)

Where each energy is the sum of kinetic energy $K$ and potential energy $U$ :

$K_{o}+U_{o}=K_{f}+U_{f}$ (2)

Where:

$K_{o}=\frac{1}{2}mV_{o}^{2}$

Being $m$ your mass and $V_{o}=0 m/s$ your initial velocity, since the roller coaster sterted from rest.

$U_{o}=mgh_{o}$

Being $g=9.8 m/s^{2}$ the acceleration due gravity and $h_{o}=25 m$ your initial height

$K_{f}=\frac{1}{2}mV_{f}^{2}$

Being $V_{f}$ your final velocity

$U_{f}=mgh_{f}$

Being $h_{f}=3 m$ your final height

Rewritting (2):

$\frac{1}{2}mV_{o}^{2}+mgh_{o}=\frac{1}{2}mV_{f}^{2}+mgh_{f}$ (3)

$mgh_{o}=m(\frac{1}{2}V_{f}^{2}+gh_{f})$ (4)

Isolating $V_{f}$ :

$V_{f}=\sqrt{2g(h_{o}-h_{f})}$ (5)

$V_{f}=\sqrt{2(9.8 m/s^{2})(25 m-3 m)}$ (6)

Finally:

$V_{f}=20.765 m/s$ This is your spedd when you arrive at 3 m height

7 0

4 years ago

Convert: Thermal conductivity value of 0.3 Btu/(h ft°F) to W/(m °C). Surface heat transfer coefficient value of 105 Btu/(h ft2 o

Finger [1]

Answer:

0.3 Btu/(h ft °F) = 0.5189 W/(m°C)

105 Btu/(h ft² °F) = 596.2215 W/(m²°C)

Explanation:

Thermal conductivity of a substance is defined as the measure of the tendency of the substance to conduct heat.

The SI unit of thermal conductivity is W.m⁻¹K⁻¹ .

From the question , 0.3 Btu/(h ft °F) is to be converted to W/(m°C)

Thus,

1 Btu/(h ft °F) = 1.7296 W/(m°C)

So,

0.3 Btu/(h ft °F) = 1.7296×0.3 W/(m°C) = 0.5189 W/(m°C)

Thus,

0.3 Btu/(h ft °F) = 0.5189 W/(m°C)

Heat transfer coefficient is defined as proportionality constant between heat flux (Thermal power per unit area) and the temperature difference of the substance for that flow of heat.

The SI unit of thermal conductivity is W.m⁻²K⁻¹ .

From the question , 105 Btu/(h ft² °F) is to be converted to W/(m²°C)

Thus,

1 Btu/(h ft² °F) = 5.6783 W/(m²°C)

So,

105 Btu/(h ft² °F) = 5.6783×105 W/(m²°C) = 596.2215 W/(m²°C)

Thus,

105 Btu/(h ft² °F) = 596.2215 W/(m²°C)

3 0

3 years ago