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AlladinOne [14]
3 years ago
6

A standard frequency for tuning musical instruments is 440 Hz for the pitch of A, denoted A4. What is the length, in meters, of

the steel rod that produces the pitch A4 as its fundamental longitudinal resonance?
Physics
1 answer:
Sophie [7]3 years ago
4 0

Answer:

Explanation:

frequency of tuning fork = 440 Hz

wave length λ = velocity of sound  / frequency

= 343 / 440 m

= .7795 m

= 77.95 cm

λ = 77.95 cm

Let length of rod having fundamental wavelength of 77.95 cm be L

L = λ  /2

L = 77.95 / 2

= 38.975 cm .

length of rod = 38.975 cm .

= 0. 39 m

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A long solenoid that has 1,140 turns uniformly distributed over a length of 0.350 m produces a magnetic field of magnitude 1.00
Troyanec [42]

Answer:

I = 2.4 *10^{-2} A = 2.4 mA

Explanation:

The magnetic field B inside long solenoid with current I is given as

B = \frac{N \mu_o I}{L}

where

N is number of turn of solenoids = 1140 turns

\mu_0 = 4*\pi *10^{-7} T.m

I is current that passes through solenoid

L is length along which current pass = 0.350 m

plugging value to get required value of current

1.00*10^{-4} = \frac{1140*4*\pi *10^{-7} I}{0.350}

I = 2.4 *10^{-2} A = 2.4 mA

3 0
3 years ago
After the ball reaches the top and begins its return back down, by how much does it speed increase each second?
FrozenT [24]

After the ball reaches the top and begins its return back down, it's just a falling object that's been dropped.  

The amount that its downward speed increases every second is just the acceleration of gravity on Earth.

That's <em>9.81 meters per second</em> every second.

7 0
4 years ago
O
lbvjy [14]

Hi there!

1.

The period of a pendulum can be calculated using the following equation:
\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}

T = period (s)

L = length of string (m)
g = acceleration due to gravity (m/s²)

Plug in the values:

T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}

2.

Calculate the period:


T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }

Frequency is the reciprocal of the period, so:


f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}

6 0
3 years ago
A 68 kgkg driver gets into an empty taptap to start the day's work. The springs compress 2.1×10−2 mm . What is the effective spr
gayaneshka [121]

Answer:

K = 3.1 8 × 10⁴ Nm

Explanation:

Given:

m = 68 Kg

x= 2.1 × 10 ⁻² m (in (2.1×10−2 mm) i think m is repeated just like kgkg in the start of question)

g=9.81 m/s²

K= ?

According to Hooke's Law

F = K x  

also F=mg

⇒ mg = Kx

⇒ K = mg/x

K= 68 Kg × 9.81 m/s² / 2.1 × 10 ⁻² m

K = 3.1 8 × 10⁴ Nm

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3 years ago
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