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True [87]
3 years ago
12

.physics wave. Please don't dare to answer irrelevant

Physics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

1a) 857143 m

1b) 414 m

2a)

2b)

3) the medium of air has a wavelength of 0.334 m, the medium of water has a wavelength of 1.493 m, and the medium of 5.130 m.

Explanation:

Question 1a)

Given the velocity/speed, and frequency of the wave, the length can be calculated using these two quantites.

[ λ = v / f ] wavelength = <u>v</u>elocity of the wave / <u>f</u>requency of the wave in Hz.

Since 3 × 10^8 × ms^-1 is the velocity, and 350Hz is the frequency.

Anything to the negative power is reciprocated. i.e ms^-1 = m/s.

The wavelength is 300000000m/350Hz = 857142.8571428..... m ≈ 857143 m

Question 1b) Given that the frequency of the second wave in water is 1% of the first wave, and the speed of the second wave is 1450ms^-1

Therefore the second wave has a frequency of 1% of 3.5 = 350/100 Hz = 3.5 Hz

The wavelength is found using the same

formula: wavelength = 1450m/3.5Hz = 414.2857142857.... m ≈ 414 m

Question 2a)

Question 2b)

Question 3) Remember, the speed of sound of the medium = frequency of the medium × wavelength of the medium.

Therefore the wavelength of the medium = speed of sound of the medium / frequency of the medium. This has a similar correlation to the wavelength formula. We are given that all these mediums have a frequency of 1KHz = 1000Hz, where So the wavelength of each medium =

Question 4)

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The distance from the central bright spot are 156.8\times10^{-3}\ mm and 142.9\times10^{-3}\ mm.

Explanation:

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Wavelength = 490 nm

Distance y= 15 mm

Length L=1.6 m

New wavelength = 670

We need to calculate the distance from the central bright spot

Using formula of distance

y= \dfrac{m\lambda L}{d}

d=\dfrac{m\lambda L}{y}

Put the value into the formula

d=\dfrac{3\times490\times10^{-9}\times1.6}{15\times10^{-3}}

d=156.8\times10^{-6}\ m

d=156.8\times10^{-3}\ mm

We need to calculate the distance from the central bright spot for new wavelength

Using formula of distance

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Put the value into the formula

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