Answer:
A.) Find the answer in the explanation
B.) Ua = 7.33 m/s , Vb = 7.73 m/s
C.) Impulse = 17.6 Ns
D.) 49%
Explanation:
Let Ua = initial velocity of the rod A
Ub = initial velocity of the rod B
Va = final velocity of the rod A
Vb = final velocity of the rod B
Ma = mass of rod A
Mb = mass of rod B
Given that
Ma = 2kg
Mb = 1kg
Ub = 3 m/s
Va = 0
e = restitution coefficient = 0.65
The general expression for the velocities of the two rods after impact will be achieved by considering the conservation of linear momentum.
Please find the attached files for the solution
Answer:
A charge q1=7.0mc is located at the origin and a second charge q2=-5.0mc is located on the x axis, 0.3m the origin find the electric field at the point p which he's coordinates (0,0.40)m
Answer:
Option D
All the above
Explanation:
Depending with the number of occupants in a building, the number of air conditioners required can either be increased or reduced. For instance, if the building is to be a classroom of over 50 students, 1 air-conditioner can't serve effectively. Similarly, the activity of occupants also dictate the amount of air conditioners required since if it's a gym room where occupants exercise often then the air conditioners required is different from if the room was to serve as a lounge. The appliances that also operate in a room require that air conditioners be installed as per the heat that may be generated by the appliances.
Answer:
The inductance of the inductor is 0.051H
Explanation:
From Ohm's law;
V = IR .................. 1
The inductor has its internal resistance referred to as the inductive reactance, X
, which is the resistance to the flow of current through the inductor.
From equation 1;
V = IX![_{L}](https://tex.z-dn.net/?f=_%7BL%7D)
X
=
................ 2
Given that; V = 240V, f = 50Hz,
=
, I = 15A, so that;
From equation 2,
X
= ![\frac{240}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B240%7D%7B15%7D)
= 16Ω
To determine the inductance of the inductor,
X
= 2
fL
L = ![\frac{X_{L} }{2 \pi f}](https://tex.z-dn.net/?f=%5Cfrac%7BX_%7BL%7D%20%7D%7B2%20%5Cpi%20f%7D)
= ![\frac{16}{2*\frac{22}{7}*50 }](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B2%2A%5Cfrac%7B22%7D%7B7%7D%2A50%20%7D)
= 0.05091
The inductance of the inductor is 0.051H.
Answer:
![V_{dc}=84.15\ V](https://tex.z-dn.net/?f=V_%7Bdc%7D%3D84.15%5C%20V)
Explanation:
Given that
Vrms= 60 V
Vf= 0.7 V
We know that peak value of AC voltage given as
![V_{o}=\sqrt{2}\ V_{rms}](https://tex.z-dn.net/?f=V_%7Bo%7D%3D%5Csqrt%7B2%7D%5C%20V_%7Brms%7D)
Now by putting the values
![V_{o}=60\sqrt{2}\ V](https://tex.z-dn.net/?f=V_%7Bo%7D%3D60%5Csqrt%7B2%7D%5C%20V)
The output voltage of the DC current given as
![V_{dc}=V_{o}-V_f](https://tex.z-dn.net/?f=V_%7Bdc%7D%3DV_%7Bo%7D-V_f)
![V_{dc}=60\sqrt{2}-0.7\ V](https://tex.z-dn.net/?f=V_%7Bdc%7D%3D60%5Csqrt%7B2%7D-0.7%5C%20V)
![V_{dc}=84.15\ V](https://tex.z-dn.net/?f=V_%7Bdc%7D%3D84.15%5C%20V)
Therefore output voltage of the DC current is 84.15 V.