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vladimir1956 [14]
3 years ago
6

What is 15% of 60? please help me ​

Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

9

Step-by-step explanation:

15 percent of 50 is 9

hope this helps

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12/6 = 4/2 true or false
alexandr402 [8]

Answer:

This is true

Step-by-step explanation:

You are division by 12/6 by 3 and that =4/2

4 0
3 years ago
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You, as a mayor of the city, need to create sufficient housing, so that there are no homeless
STatiana [176]

Answer:

The mayor will need 18 floors to each of the 10 buildings.

Step-by-step explanation:

360 buildings with 2 families per floor, that will require

360 / 2 = 180 floors.

For a limit of 10 buildings, the mayor will need

180 / 10 = 18 floors per building.

5 0
3 years ago
Please someone help me with this ASAP especially with the workout!!
Serjik [45]

Answer:

78°

Step-by-step explanation:

From the diagram,

Applying sine rule,

SinA/a = sinC/c................... Equation 1

Given: c = 29 cm, C = 50°, a = 37 cm

Substitute into equation 1 and solve for A.

sinA/37 = sin50°/29

sinA = (37×sin50°)/29

sinA = (37×0.766)/29

sinA = 28.34/29

sinA = 0.9774

A = sin⁻¹(0.9774)

A = 77.8°

A ≈ 78°

Hence the measure of angle A = 78°

6 0
3 years ago
∆ ABC is isosceles with AB= AC= 7.5cm and BC= 0 cm .the height AD from A to BC, is 6cm . find the area of ∆ ABC what will be the
lora16 [44]

I have attached an image of the triangle.

BC = 9 cm

Answer:

CE = 7.2 cm

Step-by-step explanation:

In the attached triangle, we see that;

AB = AC = 7.5cm

BC = 9 cm

AD = 6cm

BC = 9cm

Formula for area of triangle is given as;

A = ½bh

Where b is base and h is height.

For the ∆ ABC with BC as base,

Area = ½ × 9 × 6 = 27 m²

Similarly, For ∆ ABC with AB as base,

Area = ½ × 7.5 × CE

Now, area from earlier is 27 cm²

Thus;

½ × 7.5 × CE = 27

Multiply both sides by 2 to get;

7.5CE = 54

CE = 54/7.5

CE = 7.2 cm

3 0
3 years ago
Find the equation of the straight line that passes through the point (1,1/2) and has slope 1/2. Enter the equation in the point-
Nataliya [291]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 1}}\quad ,&{{ \frac{1}{2}}})\quad 
%   (c,d)

\end{array}
\\\quad \\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{1}{2}
\\ \quad \\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values}\\

\end{array}\\
\qquad \uparrow\\
\textit{point-slope form}
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3 years ago
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