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butalik [34]
3 years ago
6

Suppose a mad scientist went back in time to the beginning of the solar system and caused the newly formed Mars and Venus to swi

tch places. So now there is a Venus-sized planet where Mars was (let's call it Venus 2), and a Mars-sized planet where Venus was (let's call it Mars 2). How would these hypothetical new planets, Mars 2 and Venus 2, turn out in this alternate time line
Physics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

Mars2   illuminated side of the planet is very  heat, dark side very cool

Venus 2 a warm planet with a constant temperature across the entire surface

Explanation:

For this hypothetical case, when changing the planets they are changed with their current characteristics.

Case of Mars2

In this case, there is a planet with a very thin atmosphere, so the solar radiation reaches the ground without damping it, causing a lot of noise, so the illuminated side of the planet is very heat and when the dark side turns due to the little atmosphere it loses everything the heat for which it is very cold.

This thermal stress between the two sides of the planet continues constantly creating possible fruit trees in its rocky systems.

Case of Venus 2

The planet has a high atmospheric density, but it is very far from the sun, so the amount of radiation that arrives slightly warms the planet, but due to the thin atmosphere the losses for the dark period are very small, so the entire planet it is heated until it reaches an almost uniform temperature over its entire surface.

In this case we have a warm planet with a constant temperature across the entire surface, regardless of which side is lit.

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Light from a sodium lamp 1l = 589 nm2 illuminates two narrow slits. the fringe spacing on a screen 150 cm behind the slits is 4.
BartSMP [9]

d = 0.221 mm is the spacing (in mm) between the two slits..

here,

wavelength  = 589 nm

D = 150 cm  =  1.5 m

y  = 4 mm

then ,

y = mλD/d

for m  = `1

0.004  = 589*10^-9 * 1.5/d

d = 2.21*10^-4 m  

d = 0.221 mm

slit spacing is 0.221 mm

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7 0
2 years ago
Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspe
Elenna [48]

Answer:

dg= 942m

Explanation:

given the depth of the granite Us dg = 500m

time between the explosion t = 0.99s

the speed of sound in granite is Vg = 6000m/s

First of all calculate the time it takes the sound waves to travel down through the lake

Vw = dw/t1

t1 = dw/Vw

t1 = 500/1480

t1 = 0.338s.

Let dg be the depth of the granite basin, so the time it takes for the sound to travel down through the granite is t2 = dg/6000m/s......equation(1)

So the total time it takes to travel down to the oil surface will be

t1/2 = t1 + t2

t1/2=  0.338 + dg/6000.

since the reflection on the oil does not change the speed of sound, the sound will take travelling upto the surface the same time it takes to reach the oil

so; t = 2 t1/2

t1/2 = t/2 = 0.99s/2 = 0.495

Now insert into the values of t1/2 into the equation (1) and solve for dg;

we get 0.495 = 0.338 + dg/6000

dg = (0.495 - 0.338) x 6000

dg = 942m.

3 0
3 years ago
Read 2 more answers
The SI unit for force is the newton. Which of the following is equivalent to a newton? A. kg/m B. kg·m/s2 C. kg·m/s D. kg·m/s
bearhunter [10]
I may be wrong but A
8 0
3 years ago
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What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?
Llana [10]

Answer:

Force = 100N

Explanation:

Force = mass  × acceleration

3 0
3 years ago
A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
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