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3 years ago

Which describes the relationship between photon energy and the color of light?

Physics

2 answers:

kolbaska11 [484]3 years ago

4 0

Answer:

Red photons have the least amount of energy.

Explanation:

I did Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint Gradpoint too :) :) :)

Andrew [12]3 years ago

3 0

Photon energy is directly proportional to the frequency of electromagnetic radiation.
(That would also mean that it's inversely proportional to the wavelength.)

So the photon energy increases as you scan the chart of visible colors
moving from the red end of the rainbow to the blue end.

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An object of mass m is moving down an inclined plane that makes an angle they a with the horizontal and has height h. Which of t

Lera25 [3.4K]

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3 years ago

In any system, the _____ in the system remains constant, while the PE or KE may change.

vladimir1956 [14]

Answer:

The sum of PE and KE remains constant

Explanation:

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3 years ago

Gabriel is performing an experiment in which he is measuring the energy and work being done by a ball rolling down a hill.Which

Rufina [12.5K]

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3 years ago

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The diagram shows what happens to a system undergoing an adiabatic process.

posledela

The answer is:
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4 years ago

Read 2 more answers

A flutist assembles her flute in a room where the speed of sound is 342m/s . When she plays the note A, it is in perfect tune wi

USPshnik [31]

Answer:

a.3Hz

b.0.0034m

Explanation:

First, we know the flute is an open pipe, because open pipe as both end open and a close organ pipe as only one end close.

The formula relating the length and he frequency is giving as

$f=\frac{nv}{2l}\\$ .

a.we first determine the length of the flute at the fundamental frequency i.e when <em>n</em>=1 and when the speed is in the 342m/s

Hence from

$f=\frac{nv}{2l}\\\\l=\frac{342}{2*440}\\ l=0.389m\\$ .

since the value of the length will remain constant, we now use the value to determine the frequency when the air becomes hotter and the speed becomes 345m/s.

$f=\frac{nv}{2l} \\f=\frac{345}{2*0.389}\\f=443.4Hz$

Hence the require beat is

$B=/f_{1}-f_{2}/\\B=/440-443/\\B=3Hz$ .

b. since the length is dependent also on the speed and frequency, we determine the new length when she plays with a fundamental frequency when the speed of sound is 345m/s

using the formula

$L_{new}=\frac{v}{2f}\\\\L_{new}=\frac{345}{2*440}\\\\L_{new}=0.39204$

Now to determine the extension,

$L_{extend}=L_{new}-L_{old}\\L_{extend}=0.39204- 0.38864\\L_{extend}=0.0034m\\$

4 0

3 years ago