The fraction of energy that is lost is 25%, it depends how fast the ball was going until it lost 25% of its energy, the gravitational energy was transferred into the kinetic energy that helped the ball bounce back
Answer:
As you know, the denser objects have more weight per unit of volume, this will mean that the force that pulls down these objects is a bit larger.
This will mean that the denser objects will always go to the bottom.
This clearly implies that the red liquid, the one with one of the smaller densities, can not be at the bottom.
There are some cases where a liquid with a small density may become a lot denser as the temperature or pressure changes, and in a case like that, we could see the red liquid at the bottom, but for this case, there is no mention of changes in the temperature nor in the pressure, so this can be discarded.
The only thing that makes sense is that the red part at the bottom is the base of the tube, and has nothing to do with the red liquid.
Answer:
Explanation:
We will use the KE equation you wrote here and fill in what we are given:
and isolating the m:
which gives us
m = .50 kg
Answer:
l=3.5 x 10^-10m
Explanation:
just toook the test got it right good luck!
Answer:
65.73N
Explanation:
The frictional force is a force that opposes the motion of an object on a flat surface or an inclined surface.
It is always acting up an incline plane .
Since the pipe will tend to roll up the plane, then both the impending force P also known as frictional force and the moving force Fm both will be acting up the plane.
The net force acting up the plane is
Fnet = P + Fm... (1)
The force perpendicular to the plane known as the normal reaction R must be equal to the force acting along the ramp in other to keep the body in equilibrium i.e R = Fnet
If R = W = mgcos (theta)
and Fm = mgsin(theta)
Then mgcos theta = Fnet
mgcos (theta) = P+Fm
mgcos (theta) = P+mgsin(theta)
P = mgcos (theta) - mgsin(theta)... (2)
Given mass = 10kg
g = 9.81m/s
We can get theta from the formula;
µ = Ff/R = wsin theta/wcos theta
µ = sin theta/cos theta
µ = tan(theta)
0.3 = tan (theta)
theta = arctan0.3
theta = 16.7°
P = 10(9.81)cos16.7° - 10(9.81)sin16.7°
P = 98.1(cos16.7°-sin16.7°)
P = 98.1(0.67)
P = 65.73N
The minimum force P required to cause impending motion is 65.73N
